Skip to content
Study Hall
Lesson 7 of 10Light & Geometric Optics
Unit 4 · Lesson 7 of 10

Total Internal Reflection, the Critical Angle and Natural Phenomena

Why light trying to leave glass or water at a steep angle cannot escape at all, how to calculate the critical angle, and how refraction and total internal reflection explain fibre optics, sparkling diamonds, apparent depth, mirages, shimmering and rainbows.

4 min read9 practice questionsInteractiveAsk AI about this →

Key things to remember

  1. 1Total internal reflection needs light going from larger to smaller AND an angle of incidence greater than the critical angle.
  2. 2Critical angle: , where ; at the refracted angle is .
  3. 3Critical angles to air: water , glass () , diamond .
  4. 4Fibre optics, binocular prisms and diamond sparkle all rely on total internal reflection.
  5. 5Apparent depth (water, looking straight down) ; mirages and shimmering come from air layers with different temperatures and indices.

Every time you stream a video, the data almost certainly spent part of its journey as flashes of light inside glass fibres thinner than a hair, running under streets and across ocean floors. The light stays trapped inside the fibre even around bends, without any mirror coating. The trick is a special case of refraction called total internal reflection, and it only needs two conditions.

When light goes from a larger index to a smaller index (glass to air, water to air) it bends away from the normal, so (for any angle other than ) the refracted angle is bigger than the incident angle. As the angle of incidence increases, the refracted ray swings closer and closer to the surface. At one particular angle, called the critical angle , the refracted ray travels exactly along the surface, at to the normal. Beyond that angle there is no refracted ray at all: all of the light reflects back into the first medium.

air n = 1.00glass n = 1.5025°41.8°60°39.3°light source25° (less than 41.8°)refracts out at 39.3°,bends away from the normal41.8° = critical anglerefracted ray runs alongthe surface (90°)60° (more than 41.8°)total internal reflection:no light escapesCritical angle, glass → airsin θc = n₂ ÷ n₁= 1.00 ÷ 1.50, so θc = 41.8°Optical fibre: total internal reflection keeps the light insideglass core inside a cladding with a lower n; every reflection is above the critical angle
Fig 1Light travelling from glass (n = 1.50) toward air at three angles: below the critical angle it refracts out, bending away from the normal; at the critical angle of about 41.8° the refracted ray runs along the surface; above it the light is totally reflected. Below: light zig-zagging along a fibre-optic cable by total internal reflection.
Two conditions for total internal reflection
1) The light must be travelling from a medium with a larger index of refraction into one with a smaller index (for example glass to air). 2) The angle of incidence must be greater than the critical angle. If either condition fails, at least some light refracts out.
Set the refracted angle to 90° in Snell's law: n₁ sin θc = n₂ sin 90° = n₂. Medium 1 is the optically denser one (larger n) that the light starts in.
BoundaryCritical angle
Water () to air
Glass () to air
Crown glass () to air
Diamond () to air
Glass () to water ()
The larger the ratio of the two indices (n₁ ÷ n₂), the smaller the critical angle and the easier it is to trap light.

Total internal reflection at work

  • Fibre optics: a glass core is wrapped in cladding with a lower index. Light hits the core-cladding boundary at more than the critical angle and reflects all the way along, even around gentle bends. Fibres carry internet and phone signals and, in a medical endoscope, let a doctor see inside the body.
  • Diamonds: with a critical angle of only , light that enters a well-cut diamond reflects many times inside before escaping through the top facets, which makes it sparkle. Dispersion spreads the escaping light into flashes of colour.
  • Prisms in binoculars and periscopes: light meets the inside face of a glass prism at , more than glass's critical angle, so it is totally reflected. A prism reflects nearly 100% of the light and never tarnishes, so it beats a silvered mirror.
A Nobel Prize for light in glass
The 2009 Nobel Prize in Physics was shared by Charles Kao, for showing how to send light through glass fibres over long distances, and by Willard Boyle and George Smith for the CCD image sensor. Boyle was born in Amherst, Nova Scotia. Fibre-optic technicians who install and splice these cables are in demand across Canada.

Refraction in nature

Apparent depthairwater n = 1.33coin (real position)apparent coineyeRays bend away from the normal leaving water;traced back, they meet at a shallower image.Mirage over a hot roadcooler airlight from the skyeye“water” = image of the skyhottest air (lowest n) just above the road;light curves up toward cooler air
Fig 2Left: light from a coin on the bottom of a pool bends away from the normal as it leaves the water, and the dashed backward extensions meet at a point higher than the coin, its apparent position. Right: a mirage over a hot road, where light from the sky curves upward through layers of hot air and appears to come from the road like a puddle of water.
  • Apparent depth: light from an underwater object bends away from the normal as it leaves the water, and your brain traces it back in a straight line to a point that is too shallow. Looking nearly straight down, for water: a pool looks only deep.
  • Mirages: on a hot day, air right above a road is hotter and has a slightly lower index than the cooler air above. Light from the sky heading down at a shallow angle is bent more and more away from the normal until it curves back upward into your eye (a total internal reflection that happens gradually). You see an image of the sky on the road, which looks like water.
  • Shimmering (heat haze): pockets of warm and cool air with slightly different indices drift and mix, so the path of light through them keeps changing and objects behind them waver. Stars twinkle for the same reason.
  • Rainbows: sunlight enters a raindrop and refracts, splitting into colours (dispersion); it reflects off the back inside surface of the drop (a partial reflection, not a total one: most of the light passes out the back) and refracts again on the way out. Red light leaves at about from the direction opposite the Sun and violet at about , so you see a rainbow only with the Sun behind you.
Loading interactive…
Set glass or water to air and raise the angle of incidence past the critical angle to watch the refracted ray vanish into total internal reflection.

Worked examples

Reveal one step at a time and try to beat it to the next line.

Example 1
Find the critical angle for light travelling from glass () into air.
Example 2
Light inside a glass prism () meets the back face at to the normal. Will it escape into the air? What if the prism is under water ()?
Example 3
A swimming pool is deep. Roughly how deep does it look to someone looking straight down from above?

Where marks get lost

  • Thinking total internal reflection can happen when light goes from air into glass. It only happens going from a larger index to a smaller one.
  • Writing with the larger index on top. That gives a value greater than 1 and an error on your calculator; the smaller index goes on top.
  • Saying the refracted ray at the critical angle is at . It is at to the normal, skimming along the surface.
  • Describing a mirage as an illusion inside the brain. The light really does curve; a camera photographs a mirage too.
  • Calling the reflection inside a raindrop 'total'. It is only a partial reflection (the light meets the back of the drop below the critical angle, so most of it passes out); refraction and dispersion are what separate the colours.

Flashcards 8

Total internal reflection
Critical angle
Critical angle of water, glass (1.50), diamond
How a fibre-optic cable works
+ 4 more

Practice

1
Find the critical angle for light travelling from water () into air, to the nearest tenth of a degree.
°
2
Find the critical angle for diamond () to air, to the nearest tenth of a degree.
°
3
Find the critical angle for light going from glass () into water (), to the nearest tenth of a degree.
°
4
A transparent plastic has a critical angle of in air. What is its index of refraction, to 2 decimal places?
5
Which situation can produce total internal reflection?
6
Looking straight down, about how deep does a deep pond appear? Use and give the answer to 1 decimal place, in metres.
m
7
Match each phenomenon to its main explanation.
Light travelling through a bent glass fibre
A 'puddle' on a dry highway on a hot day
A coin in a fountain looks closer to the surface than it is
Colours of a rainbow
Distant objects wavering above a barbecue
8
At the critical angle, what is the angle of refraction, in degrees? (Type the number.)
9
Why do binoculars use glass prisms instead of silvered mirrors to fold the light path?

Spot a mistake on this page? Let us know