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Lesson 11 of 11Quantities in Chemical Reactions
Unit 3 · Lesson 11 of 11

Percentage Yield

Comparing the theoretical yield predicted by stoichiometry to the actual yield measured in the lab, and understanding why real reactions almost always produce less than the calculation predicts.

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Key things to remember

  1. 1
  2. 2Theoretical yield is calculated from stoichiometry, always based on the limiting reagent.
  3. 3Actual yield is measured experimentally and is normally less than theoretical due to side reactions, incomplete reactions, or loss during transfer/purification.
  4. 4A percent yield over 100% signals a measurement or purity error, not an unusually efficient reaction.
  5. 5Planning: predicting:
  6. 6For a multi-step process, overall yield = product of the step yields (as decimals).

Every stoichiometry calculation you've done so far predicts a theoretical yield — the maximum possible amount of product, assuming the reaction goes perfectly to completion with none of the material lost along the way. Real reactions rarely hit that number. When a chemist actually runs the reaction, weighs the real product, and gets an actual yield, it's almost always somewhat less than the theoretical prediction. Percentage yield is simply a way of expressing how close the real result came to the ideal calculation. Think of baking: a recipe that "makes 24 cookies" is a theoretical yield. If some dough sticks to the bowl and two cookies burn, you end up with 21, an actual yield of . Nothing about the recipe was wrong; real processes simply lose material. In a chemistry lab, a careful student synthesis often lands somewhere between about and , and the percent yield is a direct measure of both the reaction and the technique.

Limiting ReagentAnalogy: 1 bolt + 2 nuts → 1 assemblyyou have 6 bolts and 8 nuts8 nuts ÷ 2 = 4 assemblies possible; 6 bolts ÷ 1 = 6 assemblies possiblenuts run out first → nuts are limiting → only 4 assemblies made, 2 bolts left over (excess)Real reaction: N₂ + 3H₂ → 2NH₃given: 4 mol N₂ and 6 mol H₂4 mol N₂ needs 12 mol H₂ (only 6 mol available)6 mol H₂ needs only 2 mol N₂ (4 mol available)H₂ runs out first → H₂ is the limiting reagentproduct formed:6 mol H₂ × (2 NH₃ / 3 H₂) = 4 mol NH₃leftover excess:4 mol N₂ − 2 mol used = 2 mol N₂ left over
Fig 1Theoretical yield is calculated from the limiting reagent using ordinary stoichiometry.

Percentage Yield Formula

  • Theoretical yield is calculated from the balanced equation, always based on the limiting reagent (see the previous topic).
  • Actual yield is a measured, experimental quantity — it comes from weighing the real product on a balance, not from a calculation.

The two yields must be in the same unit (both in grams, or both in moles) so the units cancel and leave a pure percentage. The theoretical yield comes from the full stoichiometry chain you already know: identify the limiting reagent, convert it to moles, apply the mole ratio, and convert to mass of product. Percent yield matters enormously in industry, because every percent lost is raw material paid for and thrown away. It matters even more for products made in several steps, such as medicines, because the losses multiply: the overall yield is the product of the individual step yields. Three steps at each deliver barely half the theoretical product, which is why chemists work hard to raise the yield of every single step.

Why Actual Yield Is Normally Lower

  • Side reactions: some reactant is consumed by a competing reaction that doesn't produce the desired product.
  • Incomplete reaction: the reaction doesn't fully finish reacting before it's stopped or measured.
  • Loss during transfer or purification: some product sticks to glassware, is lost while filtering, or is removed while purifying the sample.
  • Impure reactants: if the starting material is not 100% pure, less of the limiting reagent is really present than its mass suggests, so less product can form.
ATheoretical yield
  • Calculated on paper from the balanced equation
  • Always based on the limiting reagent
  • The maximum possible, assuming perfect conversion and no losses
  • Unaffected by anything done in the lab
BActual yield
  • Measured on a balance after the experiment
  • Reduced by side reactions, incomplete reaction and handling losses
  • Inflated by water or impurities left in the product
  • Its sig figs come from the balance reading
A percent yield above 100% is a red flag
Since theoretical yield is the maximum possible amount, an experimental percent yield greater than 100% signals a measurement or purity problem — commonly, the collected product still contains water or other impurities adding extra mass — not an unusually efficient reaction.
What happened in the labEffect on the measured productEffect on percent yield
Product weighed before it was fully dryextra water masstoo high (can exceed 100%)
Unreacted solid reactant mixed into the productimpurity adds masstoo high
Some product spilled or stuck to the filter papermass losttoo low
Reaction stopped before it was completeless product formedtoo low
A side reaction made a different productless of the wanted producttoo low
Trace each error to the actual yield (the numerator); the theoretical yield is a calculation and is not affected.

Working Backward: Planning with Percent Yield

Once a process's typical percent yield is known, you can use it to predict or plan. Predicting is multiplication: a reaction with a yield and a theoretical yield of should give about . Planning is division, and it is where students most often slip. If you need of product and the yield is only , you must aim for a larger theoretical yield, , and then work back through the stoichiometry to find how much reactant to use. A quick reasonableness test catches the error: the planned theoretical yield must always be bigger than the amount you actually want, never smaller.

Recognising the question type
A measured mass of product together with the reactant data means percent yield: find the theoretical yield first (checking for a limiting reagent if two reactant amounts are given), then divide. A target mass of product with a stated percent yield means working backward: divide by the yield first, then do the stoichiometry in reverse.

Worked examples

Reveal one step at a time and try to beat it to the next line.

Example 1
For , of Al (limiting, ) reacts. If a student actually collects of (), calculate the percent yield.
Example 2
For , of () reacts with excess . Calculate the theoretical yield of (), then find the percent yield if is actually collected.
Example 3
For , of () decomposes completely. Calculate the theoretical yield of (), then find the percent yield if is actually obtained.
Example 4
A lime kiln operator needs of CaO () from , and the process gives an yield. What mass of () must be heated?

Where marks get lost

  • Dividing theoretical yield by actual yield instead of actual by theoretical, which gives a nonsensical result.
  • Forgetting to first calculate the theoretical yield from the limiting reagent, and instead using the full mass of a reactant that wasn't actually limiting.
  • Reporting percent yield as a decimal (e.g. "0.886") and forgetting to multiply by 100%.
  • Treating a percent yield above 100% as evidence of an efficient reaction instead of recognizing it as a sign of a measurement or purity error.
  • When planning, multiplying by the percent yield instead of dividing (e.g. instead of ), so too little reactant is used.

Flashcards 9

Percent yield formula
What is theoretical yield?
What is actual yield?
Name three reasons actual yield is normally less than theoretical.
+ 5 more

Practice

1
For , the theoretical yield of NaCl from Na was . If is actually collected, what is the percent yield?
%
2
Which of the following is NOT a normal reason actual yield falls short of theoretical yield?
3
A student reports a percent yield of 108%. What does this most likely indicate?
4
For , the theoretical yield of CaO from CaCO3 was . If is actually obtained, what is the percent yield?
%
5
Which yield should always be calculated first, before percent yield can be found?
6
Order the steps for finding percent yield when only reactant masses and actual yield are given.
  1. 1Calculate theoretical yield of product from the limiting reagent
  2. 2Multiply by 100%
  3. 3Divide actual yield by theoretical yield
  4. 4Identify the limiting reagent
7
A reaction has a theoretical yield of of product. If the percent yield is , what mass was actually obtained?
g
8
Match each term to its meaning.
theoretical yield
actual yield
percent yield
overall yield
9
of Mg burns in of (). Mg is limiting and the theoretical yield of MgO is . If of MgO is collected, what is the percent yield? Give 3 sig figs.
%
10
A student needs of NaCl () from , and the reaction gives a yield. What mass of Na () should be used? Give 3 sig figs.
g
11
A medicine is made in two steps with yields of and . What is the overall percent yield?

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