Skip to content
Study Hall
Lesson 4 of 11Matter, Chemical Trends & Bonding
Unit 1 · Lesson 4 of 11

Periodic Trends

Atomic radius, ionization energy, electron affinity, and electronegativity — and the two forces (nuclear charge and shielding) that explain every one of these trends.

5 min read11 practice questionsInteractiveAsk AI about this →

Key things to remember

  1. 1 increases across a period (more protons, same shielding); shielding increases down a group (more shells).
  2. 2Atomic radius: decreases across a period, increases down a group.
  3. 3Ionization energy: increases across a period, decreases down a group.
  4. 4Electronegativity: increases across a period, decreases down a group; fluorine (3.98) is the highest of all elements.
  5. 5Noble gases have the highest ionization energy in each period (the peak of the trend) but are left out of electron affinity and electronegativity because their shell is already full.
  6. 6Cations are smaller than their parent atoms; anions are larger. Metal reactivity increases down a group; nonmetal reactivity increases up a group.

Four properties change in predictable patterns as you move across or down the periodic table. Memorizing the directions is easy; the goal here is to understand why they happen, because every trend comes down to a tug-of-war between two things: how much positive charge the nucleus has, and how well the inner electrons shield the outer ones from it.

The two forces behind every trend

  • Effective nuclear charge (): the net positive pull a valence electron actually feels, after accounting for the nucleus's charge and the shielding from inner electrons.
  • Shielding: inner-shell (core) electrons repel and block outer valence electrons from feeling the full pull of the nucleus.
  • Distance: electrical attraction weakens quickly with distance, so an electron in a higher shell (farther out) is held more weakly than one in a lower shell.
Key idea
Across a period (left → right): protons increase but shielding stays roughly constant (no new shells are added) → increases → valence electrons are pulled in tighter and held more strongly. Down a group (top → bottom): a new shell is added each row → shielding increases faster than nuclear charge → valence electrons are farther away and held less strongly, despite more protons.
A rough estimate: each inner (core) electron cancels about one proton's pull on the valence electrons.

This rough estimate turns the trends into arithmetic. Sodium and chlorine both have 10 core electrons (shells 1 and 2), but sodium's valence electron feels a pull of about +1 while chlorine's seven valence electrons each feel about +7. Chlorine therefore holds its electrons in much closer: its radius is about 99 pm compared with 186 pm for sodium, and removing one of its electrons takes 1251 kJ/mol compared with only 496 kJ/mol for sodium. Down a group the estimate barely changes — lithium () and sodium () feel about the same net charge — but sodium's valence electron sits one shell farther out, so distance wins and it is held more weakly. That is why ionization energy falls from 520 kJ/mol for lithium to 376 kJ/mol for cesium.

Periodic Trendsperiod (left → right)group (top → bottom)Atomic radius increases ↓ and ←Ionization energy, electronegativity, electron affinity increase ↑ and →Noble gases (group 18) are usually excluded — they rarely form bonds.
Fig 1Direction of increase for atomic radius, ionization energy, electron affinity, and electronegativity across the periodic table.
Loading interactive…
Explore how atomic radius, ionization energy, and electronegativity change as you move across and down the table.

Ion size, reactivity, and answering trend questions

ACations are smaller than their atoms
  • Na (186 pm) → Na⁺ (102 pm)
  • Losing all the valence electrons empties the outer shell entirely
  • The same number of protons now pulls on fewer electrons
  • Metals shrink when they ionize
BAnions are larger than their atoms
  • Cl (99 pm) → Cl⁻ (181 pm)
  • The added electron goes into the same outer shell
  • More electron–electron repulsion spreads the cloud out
  • The same number of protons is shared among more electrons

Reactivity follows from the same ideas, but in opposite directions for metals and nonmetals. Metals react by losing electrons, so the lower the ionization energy, the more reactive the metal: reactivity increases down a group, which is why cesium reacts explosively with water while lithium only fizzes. Nonmetals react by gaining electrons, so the stronger the pull on incoming electrons, the more reactive the nonmetal: reactivity increases up a group and to the right, which makes fluorine the most reactive nonmetal of all. Put together, metallic character increases toward the bottom left of the table and nonmetallic character toward the top right.

A four-step answer for any compare question
1. Decide whether the two elements are in the same period or the same group. 2. Name what changes: across a period the proton count rises with the same shielding; down a group a new shell is added. 3. State the effect on the valence electrons: higher pulls them closer and holds them tighter; an extra shell puts them farther away and more shielded. 4. Conclude for the property asked. If the elements share neither a period nor a group, compare each to a third element that shares one with both (as in the O, F, S example below).

Worked examples

Reveal one step at a time and try to beat it to the next line.

Example 1
Which is larger: sodium (Na) or chlorine (Cl)? Explain using .
Example 2
Which has a higher first ionization energy: lithium (Li) or caesium (Cs)? Explain.
Example 3
Rank oxygen (O), fluorine (F), and sulfur (S) from lowest to highest electronegativity.
Example 4
The ions , , and all have 10 electrons. Rank them from largest to smallest and explain.

Where marks get lost

  • Thinking more protons always means a smaller atom regardless of position — this is only true moving across a period, not down a group.
  • Forgetting that ionization energy has a jump-down at the start of each new period (the new outer electron sits in a bigger shell, heavily shielded by all the full shells beneath it).
  • Calling noble gases an exception to the ionization-energy trend — they fit it, with the highest ionization energy in each period. They are the exception for electron affinity and electronegativity instead.
  • Confusing electron affinity (energy change when gaining an electron) with ionization energy (energy needed to remove an electron) — they describe opposite processes.
  • Assuming electronegativity trends apply to noble gases — noble gases are generally excluded since they don't typically form bonds.

Flashcards 10

Effective nuclear charge ()
Shielding
Atomic radius trend
Ionization energy trend
+ 6 more

Practice

1
Which factor explains why atomic radius decreases across a period?
2
Which element has the highest electronegativity of any element?
3
What term describes the net positive charge a valence electron actually feels after accounting for inner-electron shielding?
4
Why does ionization energy decrease going down a group?
5
Arrange these elements from smallest to largest atomic radius: K, Na, Li, Rb
  1. 1Na
  2. 2Rb
  3. 3K
  4. 4Li
6
Fluorine's electronegativity is 3.98 and lithium's is 0.98. What is the electronegativity difference (ΔEN) between them?
7
Which family has the highest first ionization energy in every period, because its outer shell is already full?
8
Comparing Mg and Ca (same group), which statement is true?
9
Match each term to its meaning.
Ionization energy
Electron affinity
Electronegativity
Shielding
Atomic radius
10
Using , estimate the effective nuclear charge felt by the valence electrons of sulfur (S, , arrangement 2, 8, 6).
11
Which is larger, a chlorine atom or a chloride ion (), and why?

Spot a mistake on this page? Let us know