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Lesson 9 of 11Matter, Chemical Trends & Bonding
Unit 1 · Lesson 9 of 11

Molecular Shape (VSEPR) & Polarity

How electron domains arrange themselves in 3-D space, and how shape plus bond polarity together determine whether a whole molecule is polar.

6 min read12 practice questionsInteractiveAsk AI about this →

Key things to remember

  1. 1VSEPR: electron domains (bonds + lone pairs) repel and spread to minimize repulsion, setting molecular shape.
  2. 2Lone pairs compress bond angles slightly compared to the same domain count with no lone pairs.
  3. 3A molecule is nonpolar only if its shape is symmetric AND every outer atom attached to the central atom is identical.
  4. 4Lone pairs on the central atom always break symmetry and tend to produce a net dipole.
  5. 5CH₂Cl₂ is polar (asymmetric substitution); CCl₄ is nonpolar (identical Cl atoms, perfectly symmetric tetrahedron).

Knowing a bond is polar isn't enough to know whether the whole molecule is polar — shape matters just as much. Two polar bonds pointing in exactly opposite directions can cancel out completely, while the same two bonds at an angle will not. Think of two people pulling on a box with equal force: if they pull in opposite directions the box doesn't move, but if they both pull toward the same side, even at an angle, the box slides. Carbon dioxide and water show this perfectly. Both have two polar bonds to a central atom, yet is a nonpolar gas that barely dissolves in water, while is one of the most polar substances known. The difference is entirely shape: is straight and water is bent. To predict shape, chemists use VSEPR theory, and once you can predict shape you can predict polarity, which in turn explains boiling points, solubility and even why a microwave oven heats food.

VSEPR: Valence Shell Electron Pair Repulsion
Electron domains (bonding pairs and lone pairs) around a central atom all carry negative charge, so they repel each other and spread out as far apart as possible in 3-D space. The resulting geometric arrangement is the molecule's shape.

Counting electron domains

An electron domain is any region around the central atom where electrons are concentrated. Every lone pair is one domain, and every bond to another atom is one domain, whether it is single, double or triple. That second rule surprises many students: the two double bonds in are only 2 domains, because all the electrons in a double bond sit in the same region between the same two atoms and point in the same direction. So the recipe is: draw the Lewis structure, count the atoms bonded to the central atom, add the lone pairs on the central atom, and the total sets the basic arrangement. Two domains spread to opposite sides (180°), three spread to the corners of a flat triangle (120°), and four spread to the corners of a tetrahedron (109.5°), which is the only way to get four regions equally far apart in 3-D rather than on a flat page.

VSEPR ShapesLinear180°e.g. CO₂Trigonal planar120°e.g. BF₃Bent104.5°e.g. H₂OTrigonal pyramidal107°e.g. NH₃Tetrahedral109.5°e.g. CH₄
Fig 1The five core VSEPR shapes, their bond angles, and example molecules.
DomainsLone pairsShapeBond angleExample
20Linear180°CO₂
30Trigonal planar120°BF₃
31Benta little under 120° (about 119° in SO₂)SO₂
40Tetrahedral109.5°CH₄
41Trigonal pyramidal~107°NH₃
42Bent~104.5°H₂O

Lone pairs repel more strongly than bonding pairs (they're held closer to the central atom, not stretched out along a bond), which is why bond angles shrink slightly below the 'ideal' value every time a lone pair replaces a bonding pair — 109.5° → 107° → 104.5° as lone pairs are added to a 4-domain centre. Notice that lone pairs are invisible in the name of the shape. The electron-domain arrangement counts every domain, so , and all have a tetrahedral arrangement of 4 domains. The molecular shape describes only where the atoms are: with one corner of the tetrahedron occupied by a lone pair, looks like a pyramid with N at the top; with two corners occupied, is just a bent V of three atoms.

Loading interactive…
Rotate and build different VSEPR shapes to see how domain count and lone pairs determine geometry.

From shape to overall molecular polarity

Bond Dipoles vs Net DipoleCO₂ (linear)dipoles cancel → non-polarH₂O (bent)net dipole → polarCCl₄ (tetrahedral, symmetric)symmetric → cancels → non-polarCH₂Cl₂ (asymmetric)2 different atoms → net dipole → polar
Fig 2Individual bond dipoles either cancel (symmetric shape, identical atoms) or add up to a net dipole (asymmetric shape or different atoms).
  1. Draw the Lewis structure and determine the VSEPR shape.
  2. Identify each bond dipole (arrow pointing toward the more electronegative atom).
  3. Check the molecule's symmetry: if the shape is symmetric AND every outer atom is identical, the bond dipoles cancel exactly — the molecule is nonpolar overall.
  4. If the shape is asymmetric (including lone pairs on the central atom) OR the outer atoms are different, the dipoles do not cancel — the molecule has a net dipole and is polar.
Why is CH₂Cl₂ polar but CCl₄ is not?
Both are tetrahedral with 4 bonding domains and no lone pairs. In , all four outer atoms are identical (Cl), so the four identical bond dipoles point symmetrically outward and cancel perfectly — nonpolar. In , the outer atoms are not identical (2 H, 2 Cl) — the C–Cl dipoles are much stronger than the C–H dipoles, so they don't cancel. The molecule has an uneven charge distribution and a net dipole — polar.

Recognising polar and nonpolar molecules quickly

MoleculeDomains (lone pairs)ShapeBond dipoles cancel?Polarity
2 (0)LinearYes, equal and oppositeNonpolar
3 (0)Trigonal planarYes, three equal at 120°Nonpolar
, 4 (0)TetrahedralYes, four identical atomsNonpolar
4 (0)TetrahedralNo, one outer atom differsPolar
4 (1)Trigonal pyramidalNo, lone pair on one sidePolar
, 4 (2)BentNo, dipoles at an anglePolar
The same shape can be polar or nonpolar: check both the symmetry and whether the outer atoms are identical.
Shortcuts that work in this course
Diatomic elements (, , ) are always nonpolar because ΔEN = 0. Any diatomic compound (HCl, CO) is polar because its one bond is polar. Hydrocarbons are treated as nonpolar because C–H bonds barely differ in electronegativity. A central atom with lone pairs (NH₃, H₂O, H₂S, SO₂) gives a polar molecule. A central atom with no lone pairs and identical outer atoms gives a nonpolar molecule.

Why does any of this matter? Polarity controls how molecules interact with each other and with electric fields. Polar molecules line up in an electric field, which is exactly how a microwave oven works: the rapidly reversing field twists polar water molecules back and forth, and that motion becomes heat. Polarity also predicts mixing. Polar substances tend to dissolve in polar solvents and nonpolar substances in nonpolar solvents ("like dissolves like"), which is why oil, a nonpolar hydrocarbon mixture, floats on water instead of dissolving. Finally, the net dipole decides which intermolecular forces a substance has, and that sets its melting and boiling points, the topic of the next lesson.

Worked examples

Reveal one step at a time and try to beat it to the next line.

Example 1
Predict the shape and polarity of NH₃.
Example 2
Predict the shape and polarity of CO₂.
Example 3
Explain why water (H₂O) is polar even though it's a small, simple molecule.
Example 4
BF₃ and NF₃ both have one central atom bonded to three fluorine atoms. Predict the shape and polarity of each and explain why they differ. (B 2.04, N 3.04, F 3.98)

Where marks get lost

  • Assuming a molecule with polar bonds must be polar overall — symmetric molecules like CO₂ and CCl₄ have polar bonds but are nonpolar overall.
  • Forgetting to count lone pairs on the central atom as electron domains when determining shape.
  • Mixing up electron-domain geometry (counts lone pairs) with molecular shape/geometry (describes only where the atoms are) — for water, the electron-domain arrangement is tetrahedral, but the molecular shape is bent.
  • Assuming any tetrahedral molecule is automatically nonpolar — only true if all 4 outer atoms are identical, as in CH₄ or CCl₄, not CH₂Cl₂.
  • Predicting bond angles as exactly 109.5°/120°/180° in every case, ignoring that lone pairs compress the angle slightly.

Flashcards 10

VSEPR theory
Electron domain
Tetrahedral
Trigonal pyramidal
+ 6 more

Practice

1
A central atom with 2 bonded atoms and 1 lone pair (3 domains in total) has what molecular shape?
2
Why is CCl₄ nonpolar despite having 4 polar C–Cl bonds?
3
What shape does a central atom with 2 electron domains and no lone pairs form, and what is its bond angle?
4
Is CH₂Cl₂ polar or nonpolar, and why?
5
How many total electron domains surround the central atom in water, H₂O?
6
What is the approximate bond angle in a trigonal pyramidal molecule like NH₃?
7
Order these shapes from fewest to most electron domains: trigonal planar, linear, tetrahedral
  1. 1Trigonal planar (3 domains)
  2. 2Linear (2 domains)
  3. 3Tetrahedral (4 domains)
8
Match each molecule to its correct molecular shape.
CO₂
BF₃
CH₄
NH₃
9
Which of these molecules is polar?
10
How many electron domains surround the carbon atom in CO₂?
11
What is the F–B–F bond angle, in degrees, in trigonal planar BF₃?
°
12
Name the molecular shape of NF₃ (nitrogen has 3 bonds and 1 lone pair).

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