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Lesson 4 of 6Chemical Systems and Equilibrium
Unit 4 · Lesson 4 of 6

Solubility Equilibria, Buffers and Titration

Using Ksp to find molar solubility and predict precipitation, the common ion effect, how buffers resist pH change, and how to read titration curves and find the pH at the equivalence point for strong-strong and weak-strong titrations.

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Key things to remember

  1. 1AB salt: . AB2 salt: .
  2. 2: a precipitate forms. : no precipitate. Use concentrations after mixing.
  3. 3Common ion effect: an ion already in solution lowers the solubility of a salt containing that ion.
  4. 4Buffer: weak acid + conjugate base; , and pH = pKa at half-equivalence.
  5. 5Equivalence pH: strong-strong = 7, weak acid-strong base > 7, strong acid-weak base < 7.

Barium ions are toxic, yet people drink a suspension of barium sulfate before an X-ray of the digestive system. The reason is equilibrium: barium sulfate is so slightly soluble that only a tiny concentration of ions ever enters solution, while the solid itself blocks X-rays and outlines the stomach and intestines. The same kind of equilibrium explains why some minerals form deposits, why a buffer keeps pH steady, and why the pH at the end of a titration is not always 7.

The Solubility Product, Ksp

When a slightly soluble ionic solid is in contact with its saturated solution, dissolving and precipitating happen at equal rates. The solid is left out of the expression, so the equilibrium constant is just the product of the ion concentrations, each raised to its coefficient. It is called the solubility product constant, . The molar solubility, , is the number of moles of the solid that dissolve per litre of saturated solution.

For an AB salt Ksp = s squared; for an AB2 salt Ksp = 4s cubed, because each formula unit releases two X ions.
Compare Ksp values carefully
A smaller Ksp means a less soluble salt only when the salts produce the same number of ions (for example, two AB salts). To compare an AB salt with an AB2 salt, calculate the molar solubility of each.

Predicting Precipitation with Q

When two solutions are mixed, calculate the ion product using the concentrations after mixing (remember that mixing equal volumes halves each concentration). If , the solution holds more ions than it can at equilibrium, so a precipitate forms until . If , no precipitate forms. If , the solution is exactly saturated. The common ion effect is Le Chatelier's principle applied to solubility. Dissolving AgCl in a solution that already contains (for example, from NaCl) pushes to the left, so less AgCl dissolves. The same idea explains how many kidney stones, which are often made of calcium salts, can form when the ion concentrations in urine exceed the solubility product.

Buffers

A buffer is a solution that resists changes in pH when small amounts of acid or base are added. It contains a weak acid and its conjugate base in similar amounts, such as acetic acid and sodium acetate. The weak acid neutralizes added base, and the conjugate base neutralizes added acid, The pH changes only slightly because the ratio of the two components changes only slightly. A weak base with its conjugate acid (such as with ) works the same way.

The Henderson-Hasselbalch equation: a shortcut that comes from rearranging the Ka expression for a buffer.

Titration Curves

In a titration, a solution of known concentration (the titrant, delivered from a burette) is added to a measured volume of the unknown until the equivalence point, where the moles of acid and base match the mole ratio in the balanced equation. The endpoint is where an indicator changes colour; a well-chosen indicator makes the endpoint land on or very near the equivalence point. Plotting pH against volume of titrant gives a titration curve with a steep jump near equivalence.

Titration ApparatusburettestopcockErlenmeyer flask + indicatortitrant drips inpipettemeniscus readingread at eye level,bottom of curve
Fig 1Titration apparatus: the titrant is added from a burette to the flask containing the analyte and an indicator.
Titration curves: strong acid vs weak acid25.0 mL of 0.100 mol/L acid titrated with 0.100 mol/L NaOH (Ka of CH₃COOH = 1.8 × 10⁻⁵)buffer region0246810121401020304050Volume of NaOH added (mL)pHhalf-equivalence (12.5 mL)pH = pKa = 4.74weak acid: equivalence pH ≈ 8.7above 7: acetate (CH₃COO⁻) is a weak basestrong acid: equivalence pH = 7.00only neutral Na⁺ and Cl⁻ ions remainstrong acid: HClweak acid: CH₃COOH
Fig 2A strong acid titrated with a strong base has its equivalence point at pH 7; a weak acid titrated with a strong base has a buffer region and an equivalence point above pH 7.
TitrationSpecies present at equivalencepH at equivalence
Strong acid + strong base (HCl + NaOH)Neutral salt and water (, )7.00 at 25 °C
Weak acid + strong base ( + NaOH)The conjugate base , which is weakly basicAbove 7
Strong acid + weak base (HCl + )The conjugate acid , which is weakly acidicBelow 7
Choose an indicator whose colour change range includes the pH at the equivalence point.
  • In a weak acid-strong base curve, the region before equivalence is a buffer: both HA and are present, so the pH rises slowly.
  • At the half-equivalence point, , so . This is how Ka for acetic acid can be measured from a titration curve.
  • Phenolphthalein, which changes from colourless to pink at roughly pH 8 to 10, suits a weak acid-strong base titration. Methyl orange, which changes at roughly pH 3 to 4.5, suits a strong acid-weak base titration.

Worked examples

Reveal one step at a time and try to beat it to the next line.

Example 1
Calculate the molar solubility of silver chloride in pure water. .
Example 2
A slightly soluble salt has . Calculate its molar solubility.
Example 3
of is mixed with of NaCl. Will AgCl precipitate? .
Example 4
of acetic acid () is titrated with NaOH. Calculate the pH at the equivalence point.

Where marks get lost

  • Writing for an AB2 salt. The term is , so .
  • Calculating Q for precipitation with the concentrations before mixing instead of after dilution.
  • Assuming every titration has its equivalence point at pH 7. That is only true for a strong acid with a strong base.
  • Comparing Ksp values directly for salts that release different numbers of ions.
  • Thinking a buffer keeps pH perfectly constant or works for any amount of added acid. It resists small changes, and it fails once one component is used up.

Flashcards 8

Solubility product constant,
Molar solubility
Ksp in terms of s for an AB2 salt
Condition for a precipitate to form
+ 4 more

Practice

1
A slightly soluble salt AB has a molar solubility of . Calculate its Ksp (2 significant figures, for example 3.4e-10).
2
A salt has a molar solubility of . Calculate its Ksp to 3 significant figures (for example, 2.46e-11).
3
What is the molar solubility of AgCl () in NaCl? Give 2 significant figures (for example, 3.4e-9).
mol/L
4
Equal volumes of and NaCl are mixed. With , what happens?
5
A buffer contains sodium acetate and acetic acid (). Calculate its pH to 2 decimal places.
6
of HCl is titrated with NaOH. What volume of NaOH, in mL, is needed to reach the equivalence point?
mL
7
of HCl is titrated with NaOH. What is the pH after of NaOH has been added? Give 2 decimal places.
8
Which titration has an equivalence point below pH 7?
9
Order these from lowest molar solubility to highest. Use Ksp(AgCl) = 1.8 × 10⁻¹⁰.
  1. 1AgCl in pure water
  2. 2Salt MX₂ with Ksp = 4.0 × 10⁻¹², in pure water
  3. 3Salt AB with Ksp = 4.0 × 10⁻¹⁰, in pure water
  4. 4AgCl in 0.10 mol/L NaCl
10
In a weak acid-strong base titration, the pH at the half-equivalence point equals which quantity of the weak acid?
11
Match each term to its description.
Buffer
Common ion effect
Equivalence point
Endpoint

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