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Lesson 5 of 6Chemical Systems and Equilibrium
Unit 4 · Lesson 5 of 6

Equilibrium at Work: Industry, Body and Environment

Applying K, Ksp and Le Chatelier's principle to real systems: the contact process for sulfuric acid, kidney stones and gallstones, removing heavy metals by precipitation, hard water, hemoglobin carrying oxygen or carbon monoxide, buffered medications and ocean acidification.

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Key things to remember

  1. 1Contact process: , kJ; about 400–450 °C, catalyst, excess air, 1–2 atm; a rate-versus-yield compromise.
  2. 2Kidney stones form when for calcium oxalate in urine; dilution, less oxalate and citrate lower Q.
  3. 3CO binds hemoglobin about 200 times more strongly than ; high shifts to the left.
  4. 4Heavy metals are removed by precipitating hydroxides or (more completely) sulfides with very small Ksp values.
  5. 5Heating hard water drives off and precipitates scale.
  6. 6Ocean acidification: extra converts to , lowering Q for and making shells harder to build.

Equilibrium is not just a topic for sealed flasks. A sulfuric acid plant, a kidney, the blood in your veins and the ocean are all full of reversible reactions, and in each one the same rules decide what happens: compare Q with K, and predict how the system responds to a stress. The previous lessons applied these ideas to the Haber process and the bicarbonate buffer in blood. This lesson takes them further, into an industrial process that must balance yield against rate, medical problems that are really precipitation problems, water treatment, and a global change in the chemistry of the oceans.

Industry: the contact process for sulfuric acid

The key equilibrium step: exothermic, with 3 moles of gas becoming 2.

Sulfuric acid is made in larger amounts than any other industrial chemical, mainly for phosphate fertilizers. Sulfur is burned to (or is captured from smelter gases), which is oxidized to in the step above. Le Chatelier's principle says a low temperature would give the most , since the reaction is exothermic, but the rate would be far too slow. As in the Haber process, plants compromise at about 400 to 450 °C and add a catalyst, vanadium(V) oxide, , which speeds the approach to equilibrium without changing K. High pressure would also favour the side with fewer moles of gas, but at this temperature conversion already exceeds 99% at only 1 to 2 atm when the gas passes through several catalyst beds with cooling in between, so expensive high-pressure equipment is not worth it. Excess air supplies extra , shifting the equilibrium right. is absorbed into concentrated sulfuric acid rather than water, because with water it forms a corrosive mist; the product is diluted afterward. In Sudbury, nickel smelters now capture the that once caused acid rain and turn it into sulfuric acid.

N₂(g) + 3 H₂(g) ⇌ 2 NH₃(g) ΔH = −92 kJexothermic forward reaction, so heat counts as a product · 4 mol gas on the left, 2 mol on the rightAdd N₂ (a reactant)Q drops below KN₂ + 3H₂2NH₃Shifts rightmore NH₃ forms; K unchangedRemove NH₃ (a product)also makes Q < KN₂ + 3H₂2NH₃Shifts rightmore NH₃ forms; K unchangedIncrease pressureby shrinking the volumeN₂ + 3H₂2NH₃Shifts rightfewer gas moles; K unchangedRaise temperatureheat is a product (ΔH < 0)N₂ + 3H₂2NH₃Shifts leftNH₃ decomposes; K decreasesLower temperatureremoves heat, a productN₂ + 3H₂2NH₃Shifts rightmore NH₃ forms; K increasesAdd a catalystspeeds both directionsN₂ + 3H₂2NH₃No shiftreached faster; K unchangedOnly a change in temperature changes the value of K.Concentration and pressure changes move Q away from K; a catalyst changes neither Q nor K.
Fig 1Each stress shifts an equilibrium in the direction that partly counteracts it. Industrial chemists choose concentration, pressure and temperature to push the system toward the product they want.

In the body: stones, hemoglobin and buffered medicines

About four out of five kidney stones contain calcium, most often calcium oxalate, (). Urine is often supersaturated with it (); natural inhibitors such as citrate slow crystal growth, but if Q stays high, crystals grow into stones. Every prevention strategy lowers Q. Drinking more water dilutes both ions, cutting oxalate-rich foods lowers , and potassium citrate binds in a soluble complex, lowering the free calcium ion concentration. Uric acid stones are a pH problem: uric acid is a weak acid, and in acidic urine the equilibrium favours the poorly soluble neutral form, so making urine less acidic dissolves them. Gallstones follow the same logic: most form when bile holds more cholesterol than its bile salts can keep dissolved.

Each hemoglobin molecule binds up to four molecules reversibly. In the lungs, where oxygen is plentiful, the equilibrium shifts toward oxyhemoglobin; in active tissues, where oxygen is scarce, it shifts back and releases . Carbon monoxide binds the same sites about 200 times more strongly than oxygen, so even a small concentration of CO ties up a large share of hemoglobin as carboxyhemoglobin, starving tissues of oxygen. Treatment is Le Chatelier's principle: breathing pure or pressurized oxygen raises and shifts the equilibrium below to the left, freeing hemoglobin. Ontario has required CO alarms in homes with fuel-burning appliances since 2014.

Because K is large, CO wins the competition for hemoglobin unless O₂ is far more concentrated.

Medicines use acid-base equilibria too. Aspirin is a weak acid (). Buffered aspirin includes bases such as calcium carbonate or magnesium oxide, which neutralize some stomach acid around the tablet, so it dissolves faster and may irritate the stomach lining less. Antacids raise stomach pH the same way, and many liquid medicines and eye drops contain buffers so their pH stays stable on the shelf and comfortable in the body.

The environment: hard water, heavy metals and the oceans

Groundwater flowing through limestone dissolves it: Water rich in and is hard. Heating drives out of solution, shifting the equilibrium left, so precipitates as scale in kettles and water heaters. Water softeners swap for by ion exchange, or add carbonate so the common ion precipitates . Industrial wastewater is cleaned of heavy metals the same way: adding lime raises until metal hydroxides such as () precipitate, leaving tiny dissolved concentrations. Metal sulfides have even smaller Ksp values, so sulfide precipitation removes metals more completely. The pH must be controlled, because some hydroxides redissolve as complex ions in strongly basic solution.

The oceans absorb about a quarter of the humans emit. Dissolved forms carbonic acid, which releases : . Much of that then combines with carbonate ions, , lowering . Surface ocean pH has fallen from about 8.2 before industrialization to about 8.1. For corals, oysters and plankton that build shells from calcium carbonate, lower means a smaller Q for , so building shells costs more energy, and where Q falls below Ksp, shells begin to dissolve.

SystemEquilibriumStressResult
Contact processExcess ; moderate temperature with High yield at a practical rate
Kidney stone preventionDilution; citrate binds Q falls toward or below Ksp
CO poisoning treatmentPure or pressurized Shifts left, freeing hemoglobin
Kettle scaleHeating removes Shifts left; precipitates
Ocean acidificationAdded removes Shells harder to build or dissolve
The same reasoning in five settings: identify the equilibrium, name the stress, predict the shift.

Worked examples

Reveal one step at a time and try to beat it to the next line.

Example 1
Predict and explain the effect of each condition on the yield and rate of kJ: (a) excess air, (b) a temperature of 450 °C rather than 200 °C, (c) a catalyst, (d) a pressure of 1–2 atm rather than 200 atm.
Example 2
A patient's urine contains mol/L and mol/L. for calcium oxalate is . (a) Is the urine supersaturated? (b) What is Q if the patient doubles their urine volume by drinking more water?
Example 3
Wastewater containing is treated with lime until the pH is 9.00. Using for , find the maximum remaining in mol/L and in mg/L ( g/mol).
Example 4
For , . In a garage, air contains 0.050% CO and 21% . Estimate the ratio at equilibrium and the percentage of this hemoglobin bound to CO.

Where marks get lost

  • Saying the contact process uses 450 °C because it gives the highest yield. Low temperature gives the highest yield for this exothermic reaction; 450 °C is chosen for rate, with a catalyst.
  • Thinking the catalyst increases the amount of at equilibrium. only speeds up reaching equilibrium.
  • Comparing Q with Ksp using concentrations before dilution or mixing. Always use the concentrations actually present.
  • Saying CO poisoning is treated by removing CO from the blood directly. Treatment raises , which shifts the hemoglobin equilibrium to release CO.
  • Thinking ocean acidification means the ocean has become acidic. Its pH is still above 7; it has become less basic, and the lower carbonate ion concentration is what harms shell builders.

Flashcards 9

Contact process key step
Why SO₃ is absorbed in concentrated H₂SO₄
Calcium oxalate kidney stones
Carboxyhemoglobin
+ 5 more

Practice

1
Why is the contact process run at about 450 °C even though the oxidation of SO₂ is exothermic?
2
Urine contains mol/L and mol/L. Calculate Q for calcium oxalate, in units of . (1 decimal place)
× 10⁻⁷
3
Wastewater is brought to pH 10.00. Using for , what is the maximum , in units of mol/L? (1 decimal place)
× 10⁻¹² mol/L
4
Surface ocean pH has fallen from 8.2 to 8.1. By what percentage has increased? (whole number)
%
5
Why does a kettle used with hard water build up a white scale?
6
Why is breathing pure oxygen an effective treatment for carbon monoxide poisoning?
7
Why is sulfide precipitation often more effective than hydroxide precipitation for removing heavy metals?
8
Put the steps of the contact process in order.
  1. 1Pass SO₂ and excess air over V₂O₅ at about 450 °C to make SO₃
  2. 2Dilute the product with water to the required concentration
  3. 3Absorb SO₃ in concentrated sulfuric acid
  4. 4Burn sulfur in air to make SO₂
9
Match each problem to the equilibrium-based solution.
Kidney stones
Carbon monoxide poisoning
Lead in industrial wastewater
Hard water
Slow SO₃ formation
10
Give the name or formula of the catalyst used to oxidize SO₂ to SO₃ in the contact process.
11
Which ion's concentration falls in seawater as it absorbs CO₂, making it harder for corals and shellfish to build calcium carbonate? (name or formula)

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