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Lesson 6 of 12Solutions & Solubility
Unit 4 · Lesson 6 of 12

Ions in Solution & Precipitation Reactions

Writing formula, total ionic, and net ionic equations for precipitation reactions using solubility rules to predict spectator ions.

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Key things to remember

  1. 1All Group 1 and NH4+ compounds are soluble; all nitrates and acetates are soluble — no exceptions.
  2. 2AgCl, PbI2, PbCl2, Hg2Cl2 type halides are insoluble; BaSO4, PbSO4, SrSO4 are insoluble sulfates.
  3. 3Carbonates, phosphates, hydroxides, and sulfides are generally insoluble (except with Group 1/NH4+).
  4. 4Total ionic equation: split every aqueous (soluble) compound into ions; keep solids/liquids/gases whole.
  5. 5Net ionic equation: cancel spectator ions (identical ions unchanged on both sides) from the total ionic equation.

When two clear, colourless solutions are mixed and a cloudy solid suddenly forms, something interesting has happened: the ions floating around in each solution have found new partners, and one of those new combinations is insoluble. This is a precipitation (double-displacement) reaction, and being able to predict — and correctly write out — what happens is one of the most useful skills in this unit. Remember what a solution of an ionic compound really contains: not 'NaCl molecules' but separate, hydrated and ions moving independently. When you pour two ionic solutions together, you are really pouring four kinds of ions into one beaker. Every cation meets every anion, and if any cation–anion pair cannot stay dissolved, those ions clump together and fall out of solution as a solid.

Solubility rules: why some ionic compounds don't dissolve

Dissolving an ionic solid is a tug-of-war. The ions in the crystal attract each other strongly; water molecules pull the ions out by surrounding them (hydration). If the attraction of water for the ions wins, the compound dissolves. If the ions attract each other more strongly than water can pull them apart, the compound stays solid. Ions carrying charges of 2 or 3 (such as with , or with ) hold each other very tightly, which is why most carbonates, phosphates and hydroxides of metals other than Group 1 are insoluble. Singly charged ions like , and are held loosely, so their compounds nearly always dissolve. You don't need to calculate this — the solubility table summarises the results of experiments — but it explains why the rules look the way they do. 'Insoluble' in these rules really means very slightly soluble: less than about 0.1 g dissolves per 100 mL, so the vast majority of the ions come out as a solid. A solubility table tells you which combinations of ions form soluble (stays dissolved, stays aqueous) vs. insoluble (forms a solid precipitate) compounds. Read it by checking the anion first, then looking for exceptions involving the cation. A few high-yield rules:

  • Soluble: all Group 1 (alkali metal, e.g. , ) and compounds — no exceptions.
  • Soluble: all nitrates () and acetates () — no exceptions.
  • Soluble (with exceptions): most chlorides, bromides, and iodides — EXCEPT those of , , and , which are insoluble.
  • Soluble (with exceptions): most sulfates — EXCEPT , , (insoluble) and (only slightly soluble).
  • Generally INSOLUBLE (unless paired with Group 1 or ): carbonates (), phosphates (), hydroxides (), and sulfides (). Exception: is slightly soluble; and are soluble.
Solubility RulesIonSolubilityExceptionsGroup 1 (Li⁺, Na⁺, K⁺…), NH₄⁺always solublenoneNO₃⁻, C₂H₃O₂⁻ (acetate)always solublenoneCl⁻, Br⁻, I⁻solubleexcept with Ag⁺, Pb²⁺, Hg₂²⁺SO₄²⁻solubleexcept with Ca²⁺, Sr²⁺, Ba²⁺, Pb²⁺OH⁻insolubleexcept group 1, NH₄⁺, and slightly Ca²⁺/Sr²⁺/Ba²⁺CO₃²⁻, PO₄³⁻, S²⁻insolubleexcept group 1 and NH₄⁺
Fig 1Quick-reference solubility rules for common ion combinations.

Three ways to write a precipitation reaction

Take mixing lead(II) nitrate solution with potassium iodide solution — a classic demonstration that produces a bright yellow precipitate of lead(II) iodide. The same reaction can be written at three levels of detail. Use a four-step method every time: (1) write the ions present in each solution; (2) swap partners to find the two possible new compounds, writing each formula so its charges balance; (3) check each new compound against the solubility table and mark it (aq) or (s); (4) balance the formula equation, split every (aq) compound into ions, and cancel what appears unchanged on both sides. If both possible products are (aq), write 'no reaction' — all four ions simply stay mixed in solution.

  • Formula equation — shows complete, neutral formulas, exactly as you'd write any balanced equation.
  • Total ionic equation — rewrites every soluble (aqueous) compound as its separate ions; only the insoluble precipitate is written as a whole formula, since it doesn't dissociate.
  • Net ionic equation — cancels out any ion that appears unchanged on both sides (these are called spectator ions, since they don't participate in forming the precipitate), leaving only the ions that actually react.
Formula equation.
Total ionic equation — every aqueous compound is split into its free ions.
Net ionic equation — K+ and NO3- are spectator ions and are cancelled out.
From Formula to Net Ionic Equation1. Formula equationAgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)split strong electrolytes into ions2. Total ionic equationAg⁺ + NO₃⁻ + Na⁺ + Cl⁻ → AgCl(s) + Na⁺ + NO₃⁻Na⁺ and NO₃⁻ appear unchanged on both sides — spectator ions (crossed out)remove spectator ions3. Net ionic equationAg⁺(aq) + Cl⁻(aq) → AgCl(s)the net ionic equation shows only the species that actually react
Fig 2The flow from formula equation to total ionic equation to net ionic equation, cancelling spectator ions.

Why bother with the net ionic equation? Because it shows the chemistry that actually happens, stripped of bystanders. Any soluble lead(II) salt mixed with any soluble iodide gives exactly the same net reaction, , whether the spectators are and or and . The net ionic equation is also what you use for stoichiometry: it tells you the mole ratio of the ions that form the solid. A good check: a correct net ionic equation is balanced for BOTH atoms and total charge (here, and add to zero on the left, matching the neutral solid).

Precipitation at work: water treatment and testing

Precipitation reactions are the everyday tools of water chemistry. Hard water contains dissolved and ; when it is heated, carbonate ions form and precipitates as the scale that coats kettles and hot-water pipes. Municipal treatment plants add aluminum sulfate (alum) or iron(III) salts, which form gelatinous hydroxide precipitates such as that trap suspended clay and bacteria as they settle. Wastewater plants remove phosphate — which would otherwise feed algae blooms in lakes — by precipitating it as insoluble iron(III) or aluminum phosphate. And in the lab, adding to a water sample and weighing the white that forms is a classic way to measure chloride content. In each case the chemist chooses an added ion that forms an insoluble compound with the unwanted ion, while its partner ion is a harmless spectator.

How to recognise the question type
'Will a precipitate form?' needs only steps 1–3 of the method. 'Write the net ionic equation' needs all four. 'Which reagent would remove ion X?' is the reverse problem: find an ion that forms an insoluble compound with X, then pair it with a Group 1 cation or nitrate so the reagent itself dissolves (to remove , add ). 'What mass of precipitate forms?' is solution stoichiometry, covered later in this unit.

Worked examples

Reveal one step at a time and try to beat it to the next line.

Example 1
Predict whether a precipitate forms when solutions of silver nitrate (AgNO3) and sodium chloride (NaCl) are mixed, and identify it.
Example 2
Write the formula equation, total ionic equation, and net ionic equation for mixing barium chloride (BaCl2) solution with sodium sulfate (Na2SO4) solution.
Example 3
Two solutions, KNO3 and NaCl, are mixed. Explain why no precipitate forms.
Example 4
A wastewater sample contains dissolved iron(III) chloride. A technician adds sodium hydroxide solution to remove the iron. Write the balanced formula, total ionic and net ionic equations, and name the spectator ions.

Where marks get lost

  • Writing the precipitate as split into ions in the total ionic equation — only AQUEOUS (soluble) compounds get split; solids, liquids, and gases stay as whole formulas.
  • Forgetting to balance charge and atoms when splitting compounds into ions (e.g. writing Ba2+ but forgetting the 2 in front of Cl- when balancing BaCl2).
  • Cancelling ions that aren't actually identical on both sides (different charges or different states don't count as the same spectator ion).
  • Assuming any double-displacement reaction produces a precipitate — many combinations (like KNO3 + NaCl) produce only soluble products and no reaction of interest occurs.
  • Mixing up which ion is the cation and which is the anion when predicting the new formula's subscripts (e.g. forgetting Pb2+ needs two I- ions to balance charge in PbI2).

Flashcards 9

Spectator ion
Total ionic equation
Net ionic equation
Are all nitrates soluble?
+ 5 more

Practice

1
Which pair of solutions will produce a precipitate when mixed?
2
In a total ionic equation, how should an insoluble precipitate be written?
3
What term describes ions that appear unchanged on both sides of a total ionic equation?
4
In the net ionic equation Pb2+(aq) + 2I-(aq) → PbI2(s), what is the coefficient of I-?
5
Put the steps for writing a net ionic equation for a precipitation reaction in order.
  1. 1Split every (aq) compound into ions (total ionic equation)
  2. 2Write the balanced formula equation
  3. 3Cancel spectator ions to leave the net ionic equation
  4. 4Write the ions present in each reactant solution
  5. 5Swap partners to find the possible products, balancing charges
  6. 6Use the solubility table to label each product (aq) or (s)
6
Match each compound to its solubility.
AgCl
NH4NO3
BaSO4
K2CO3
7
Write the formula for the precipitate formed when Pb(NO3)2 and KI solutions are mixed.
8
What are the spectator ions when aqueous calcium chloride is mixed with aqueous sodium carbonate?
9
A water sample contains dissolved ions. Which solution, added in excess, would remove the lead as a precipitate while adding only soluble ions?
10
In the balanced net ionic equation for mixing aqueous aluminum nitrate with sodium hydroxide, what is the coefficient of (lowest whole numbers)?
11
Aqueous silver nitrate is added to tap water and a white precipitate forms. Write the formula of the precipitate, assuming the water contains dissolved chloride.

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