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Lesson 7 of 8Gases & Atmospheric Chemistry
Unit 5 · Lesson 7 of 8

Gas Stoichiometry

Stoichiometry problems involving gas volumes use the same mole-ratio road map as any other stoichiometry problem — gas volume is just another quantity to convert to and from moles.

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Key things to remember

  1. 1Gas stoichiometry road map: given quantity → moles (molar mass, molar volume, or ideal gas law) → mole ratio → moles of target → target quantity.
  2. 2Use = 22.4 L/mol (STP) or 24.8 L/mol (SATP) only when the gas is exactly at that standard condition.
  3. 3Use for gases at non-standard conditions.
  4. 4For two gases at the SAME , their volume ratio equals their mole ratio (from the balanced equation's coefficients), by Avogadro's law.
  5. 5Dalton's law: ; for a gas collected over water, .

By this point you've solved stoichiometry problems converting between grams of one substance and grams of another, always by routing through moles using the balanced equation's mole ratio. Gas stoichiometry is exactly the same skill with one new twist: instead of (or in addition to) grams, you might be given or asked for the volume of a gas. The mole ratio "road map" doesn't change — you just need an extra conversion step to get gas volume into moles, or moles into gas volume.

The road map, extended for gases

Recall the general stoichiometry road map: convert the given quantity to moles, use the mole ratio from the balanced equation to convert to moles of the desired substance, then convert those moles to whatever unit is requested. Gas volume slots into this exactly like mass did — you just choose the correct conversion tool depending on the conditions given.

  1. Write and balance the chemical equation (if not already given).
  2. Convert the given quantity to moles: use molar mass for a mass in grams, or use molar volume ( = 22.4 or 24.8 L/mol) if the gas is AT STP or SATP, or use the ideal gas law () if the gas is at non-standard conditions.
  3. Use the mole ratio from the balanced equation to convert moles of the given substance to moles of the desired substance.
  4. Convert moles of the desired substance to whatever final unit is requested: grams (molar mass), volume at STP/SATP (molar volume), or volume at other conditions (ideal gas law, solved for ).
Molar Volume at STPH₂1 mol = 22.4 L6.022×10²³ particlesO₂1 mol = 22.4 L6.022×10²³ particlesCO₂1 mol = 22.4 L6.022×10²³ particlessame volume, same particle count, different mass — this only works because gases are mostly empty spaceSTP (0 °C, 100 kPa): 22.4 L/mol — SATP (25 °C, 100 kPa): 24.8 L/mol
Fig 1Molar volume is one of several tools (alongside molar mass and the ideal gas law) for converting into/out of moles during stoichiometry.
Choosing the right mole↔volume tool
If the problem says the gas is at STP or SATP, use the matching fixed molar volume (22.4 or 24.8 L/mol) — it's faster. If the problem gives a specific, non-standard pressure and temperature (e.g., "at 150 kPa and 350 K"), you must use the full ideal gas law, or , since a fixed molar volume doesn't apply outside STP/SATP.

The volume-to-volume shortcut

One more subtlety worth noting: when a balanced equation involves TWO gases (for example, both a reactant and a product are gases at the same conditions), the coefficients in the balanced equation directly give you a volume ratio too — by Avogadro's law, equal moles of gas at the same and occupy volumes in the same ratio as their mole ratio. This can occasionally save you a step, though solving through moles always works and is the safer default. Joseph Louis Gay-Lussac noticed this pattern in 1808, long before anyone could count molecules: reacting gases always combine in small whole-number volume ratios (his law of combining volumes). For the Haber process that makes ammonia for fertilizer, 10.0 L of nitrogen reacts with exactly 30.0 L of hydrogen to give 20.0 L of ammonia, all measured at the same temperature and pressure. Notice that volume is NOT conserved (40.0 L of reactants make 20.0 L of product), even though mass is: the number of gas particles drops, so the volume drops. The shortcut only applies to gases; a solid or liquid in the equation still needs its own mole conversion.

At the same temperature and pressure, gas volumes react in the same 1 : 3 : 2 ratio as the coefficients.

Dalton's law of partial pressures

Many real gas samples are mixtures: air, the gas in a scuba tank, or a gas collected in a lab. The kinetic molecular theory says ideal gas particles ignore each other except when they collide, so in a mixture each gas behaves as if it were alone in the container. Each gas's collisions with the walls produce its own partial pressure, and the total pressure is just the sum. This is Dalton's law of partial pressures. Because pressure depends only on the number of particles, each gas's share of the total pressure equals its share of the moles (its mole fraction). Air is 20.95% oxygen by volume, so at sea level (101.3 kPa) the partial pressure of oxygen is kPa. On the summit of Mount Everest the total pressure is only about 33.7 kPa, so the oxygen partial pressure falls to about 7.1 kPa. The air is still 21% oxygen, but each breath delivers only about one-third as many oxygen molecules, which is why most climbers carry bottled oxygen.

Dalton's law: partial pressures add up to the total, and each gas's share matches its share of the moles.

Collecting a gas over water

A common way to collect a gas made in a reaction (such as hydrogen from zinc and hydrochloric acid, or oxygen from decomposing hydrogen peroxide) is to bubble it into an upside-down bottle or graduated cylinder filled with water. The gas pushes the water out, and the volume can be read directly. Before reading, the cylinder is raised or lowered until the water level inside matches the level outside; then the gas inside is at the same pressure as the atmosphere. But the collected gas is not pure: water evaporates into it, so the cylinder holds a mixture of the gas and water vapour. By Dalton's law, the pressure of the dry gas is the atmospheric pressure minus the vapour pressure of water, which depends only on the temperature.

Temperature (°C)Vapour pressure of water (kPa)
182.06
202.34
222.64
242.98
253.17
263.36
283.78
304.25
Water's vapour pressure rises with temperature because more molecules have enough energy to escape the liquid.
Subtract the water vapour first
For a gas collected over water, find the dry-gas pressure BEFORE using : . Using the full atmospheric pressure overstates the moles of gas by a few percent, which is enough to make a percent-yield calculation wrong. The volume and temperature stay the same, because both gases share the whole cylinder at the same temperature.

Worked examples

Reveal one step at a time and try to beat it to the next line.

Example 1
What volume of gas at STP is needed to completely react with 4.00 g of magnesium?
Example 2
Propane burns as . What volume of (at SATP) forms from the complete combustion of 2.20 g of propane (molar mass 44.11 g/mol)?
Example 3
How many moles of gas are needed to produce 5.00 L of gas, both measured at 200.0 kPa and 320.0 K?
Example 4
Zinc reacts with hydrochloric acid: The hydrogen is collected over water at 22°C and an atmospheric pressure of 99.8 kPa, giving 0.250 L of gas. What mass of zinc reacted? (Vapour pressure of water at 22°C = 2.64 kPa.)

Where marks get lost

  • Using STP's 22.4 L/mol for a gas that is actually described at SATP or at other non-standard conditions.
  • Forgetting the mole-ratio step entirely — converting given volume straight to moles and then straight back to a volume of a DIFFERENT substance without applying the balanced equation's coefficients.
  • Trying to directly compare volumes of two gases at DIFFERENT temperatures/pressures as if they were in the same ratio as moles — the volume-ratio shortcut only works when both gases are at the SAME conditions.
  • Forgetting to balance the chemical equation first, which throws off every mole ratio downstream.
  • Using the wrong molar mass or arithmetic slip when converting grams to moles as the first step.

Flashcards 9

What extra conversion does gas stoichiometry add to the standard mole-ratio road map?
When can you use a fixed molar volume in a stoichiometry problem?
When must you use the ideal gas law instead of molar volume in stoichiometry?
When can you compare two gas volumes directly using mole ratio coefficients (no mole conversion needed)?
+ 5 more

Practice

1
For , what volume of gas at STP is needed to react completely with 3.00 mol of ?
L
2
A stoichiometry problem gives you 3.50 g of a solid reactant and asks for the volume of a gaseous product at 180.0 kPa and 310.0 K. Which tool should you use to convert final moles of product to volume?
3
In your own words, describe the general road map for a stoichiometry problem that starts with a gas volume and asks for a mass.
4
For , how many moles of are needed to produce 12.4 L of at SATP?
mol
5
Order the steps to find the volume of a gaseous product, starting from a given mass of reactant.
  1. 1Apply the mole ratio from the balanced equation
  2. 2Convert given mass to moles using molar mass
  3. 3Convert moles of product to volume using molar volume or the ideal gas law
6
Propane burns as What volume of is needed to burn 2.00 L of propane, both at the same temperature and pressure?
L
7
A gas mixture contains 0.40 mol and 0.10 mol at a total pressure of 150 kPa. What is the partial pressure of ?
kPa
8
Oxygen is collected over water at 25°C when the atmospheric pressure is 101.0 kPa. The vapour pressure of water at 25°C is 3.17 kPa. What is the pressure of the dry oxygen? Round to one decimal place.
kPa
9
Match each situation to the right tool for converting between gas volume and moles.
Gas at 0°C and 101.325 kPa
Gas at 25°C and 100.0 kPa
Gas at 150 kPa and 350 K
Two gases at the same T and P
10
Why must the vapour pressure of water be subtracted when a gas is collected over water?
11
At the same temperature and pressure, 10.0 L of reacts completely with to form (). What is the total volume of gas before and after the reaction?

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