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Lesson 4 of 6Organic Chemistry
Unit 1 · Lesson 4 of 6

Organic Reactions

Addition, substitution, elimination, oxidation of alcohols, esterification, hydrolysis and combustion: what changes in each reaction type and how to predict the products.

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Key things to remember

  1. 1Addition: atoms add across C=C or C≡C to give one saturated product; with HX or H₂O, H adds to the carbon that already has more H (Markovnikov's rule).
  2. 2Substitution: one atom or group replaces another, e.g. in UV light; benzene substitutes rather than adds.
  3. 3Elimination: removing (from an alcohol) or HX (from a haloalkane) from neighbouring carbons forms a C=C.
  4. 4Oxidation: primary alcohol → aldehyde → carboxylic acid; secondary alcohol → ketone; tertiary alcohol → no reaction.
  5. 5Carboxylic acid + alcohol ⇌ ester + water (acid catalyst, heat); hydrolysis reverses it.
  6. 6Complete combustion of a hydrocarbon gives and ; too little oxygen also gives CO and soot.

Organic molecules can look complicated, but reactions almost always happen at the functional group while the rest of the carbon skeleton comes along unchanged. That means you do not have to memorize thousands of reactions. Learn a small set of reaction types, learn which functional groups undergo each one, and you can predict the product of a reaction you have never seen. For every reaction, ask three questions: which functional group is reacting, what reagent or condition is present, and which bonds break and form?

substitution+ X₂, UV lightsubstitution+ OH⁻addition+ H₂ (Pt)addition+ HX or X₂eliminationaddition (+ H₂O)oxidation [O] of 1°oxidation [O] of 2°oxidation[O]esterification+ acid, H₂SO₄loses H₂O+ carboxylic acidhydrolysis+ H₂OAlkaneAlkyl halideAlkeneAlcoholCarboxylic acidAldehydeKetoneEster3° alcohols do not oxidizehydrolysis splits an ester back into acid + alcoholcombustion: hydrocarbons and alcohols + O₂ → CO₂ + H₂O (+ energy)
Fig 1How the main families convert into one another, with each arrow labelled by its reaction type.
Reaction typeWhat happensExample
AdditionAtoms add across a C=C or C≡C; the multiple bond becomes a single bond; one product
SubstitutionOne atom or group replaces another; two products
EliminationAtoms are removed from neighbouring carbons, forming a C=C
OxidationA carbon gains bonds to O or loses H
EsterificationCarboxylic acid + alcohol form an ester and water
HydrolysisWater splits a molecule (the reverse of esterification)
CombustionBurning in oxygen
The seven reaction types in this topic.

Combustion is the most familiar organic reaction: hydrocarbons and most other organic compounds burn. With plenty of oxygen, complete combustion turns all the carbon into carbon dioxide and all the hydrogen into water, releasing a lot of energy, which is why alkanes are fuels: . With too little oxygen, incomplete combustion also forms carbon monoxide (a toxic, colourless, odourless gas) and soot (carbon). That is why fuel-burning appliances need ventilation and homes need carbon monoxide alarms. To balance a combustion equation, balance C first, then H, then O last, doubling everything if you end up needing half an .

Addition Reactions

  • Hydrogenation: an alkene plus hydrogen, with a metal catalyst such as Pt, Pd or Ni, gives an alkane: An alkyne can add two .
  • Halogenation: an alkene plus or gives a dihaloalkane: ethene + bromine gives 1,2-dibromoethane. Orange-brown bromine water turns colourless when it reacts, so this is a quick test for C=C or C≡C bonds.
  • Hydrohalogenation: an alkene plus HCl or HBr gives a haloalkane: ethene + HBr gives bromoethane.
  • Hydration: an alkene plus water, with an acid catalyst, gives an alcohol: ethene + water gives ethanol.
  • Addition only happens at multiple bonds. Alkanes are already saturated, and benzene resists addition because it would lose its stable ring of shared electrons.
Markovnikov's rule
When H–X or H–OH adds to an alkene whose two double-bond carbons are different, the H goes mainly to the carbon that already has more H atoms, and the X or OH goes to the other carbon. Propene, , plus HBr gives mostly 2-bromopropane, not 1-bromopropane; propene plus water gives mostly propan-2-ol. For symmetrical alkenes such as ethene or but-2-ene, both carbons give the same product, so the rule does not matter.

Substitution and Elimination

In a substitution, one atom or group swaps places with another, so there are two reactants and two products. Alkanes react with chlorine or bromine only when UV light supplies energy: gives chloromethane. Benzene also undergoes substitution rather than addition: with bromine and an iron(III) bromide catalyst it forms bromobenzene and HBr, keeping its ring intact. A haloalkane heated with aqueous hydroxide swaps its halogen for –OH: An elimination is the reverse of an addition: a small molecule is removed from two neighbouring carbons and a double bond forms between them. Heating an alcohol with concentrated sulfuric acid removes (dehydration): ethanol gives ethene. Heating a haloalkane with a strong base dissolved in ethanol removes H and the halogen, giving an alkene.

Oxidation of Alcohols

Alcohol typeThe –OH carbon is bonded toExampleProduct with an oxidizing agent
Primaryone other carbon (two H atoms on it)ethanol, aldehyde (ethanal, ), then carboxylic acid (ethanoic acid, )
Secondarytwo other carbons (one H on it)propan-2-ol, ketone (propanone, ); no further oxidation
Tertiarythree other carbons (no H on it)2-methylpropan-2-ol, no reaction
Oxidation removes the H from the O–H and an H from the carbon bearing it, so that carbon needs at least one H.

Common oxidizing agents are acidified potassium dichromate, which changes from orange to green as it reacts, and acidified potassium permanganate, which changes from purple to colourless. Chemists write the oxidizing agent as [O]. A primary alcohol first forms an aldehyde; if the aldehyde stays in the mixture it is oxidized further to a carboxylic acid, so to collect the aldehyde it is distilled off as it forms (it boils lower than the alcohol because it cannot hydrogen bond). A tertiary alcohol leaves dichromate orange, which is how you can tell the three alcohol types apart in the lab.

Esterification and Hydrolysis

Ethanoic acid and ethanol form ethyl ethanoate. The acid loses its OH and the alcohol loses its H, which together make water.

Esterification is a condensation reaction: two molecules join and a small molecule (water) is released. It needs heat and a few drops of concentrated sulfuric acid as a catalyst, and it is reversible, so the mixture never turns completely into ester. Hydrolysis runs the reaction backward: water splits the ester into its carboxylic acid and alcohol, helped by an acid catalyst. Hydrolysis with a base such as NaOH goes to completion and gives the salt of the acid instead: Base hydrolysis of fats, which are esters, is how soap is made (saponification). Amides can be hydrolyzed in the same way, giving a carboxylic acid and an amine or ammonia.

Predicting a product in four moves
1) Circle the functional group in each reactant. 2) Use the reagent to pick the reaction type: and a flame means combustion, , , HX or with an alkene means addition, dichromate or permanganate means oxidation, an acid with an alcohol means esterification. 3) Break and form only the bonds that reaction type changes. 4) Count every atom on both sides before you name the product.

Worked examples

Reveal one step at a time and try to beat it to the next line.

Example 1
Predict the major product when HBr reacts with propene, .
Example 2
Each of butan-1-ol, butan-2-ol and 2-methylpropan-2-ol (all ) is warmed with acidified potassium dichromate. Predict what happens to each.
Example 3
Write the condensed equation and name the ester formed when propanoic acid reacts with ethanol.
Example 4
What mass of carbon dioxide forms from the complete combustion of 22.0 g of propane? (C = 12.01, H = 1.01, O = 16.00)

Where marks get lost

  • Putting the H on the wrong carbon when HBr or water adds to an unsymmetrical alkene, e.g. giving 1-bromopropane as the main product from propene instead of 2-bromopropane.
  • Oxidizing a secondary alcohol to an aldehyde or acid, or claiming a tertiary alcohol oxidizes; count the H atoms on the carbon bearing the –OH.
  • Leaving water out of an esterification or hydrolysis equation, so the atoms do not balance.
  • Calling a reaction with two products an addition: an addition to an alkene gives one product, while a substitution always gives two.
  • Expecting benzene to add bromine like an alkene; it keeps its ring and undergoes substitution instead.

Flashcards 9

Addition reaction
Substitution reaction
Elimination reaction
Markovnikov's rule
+ 5 more

Practice

1
Classify the reaction (in UV light).
2
What forms when propan-2-ol is oxidized with acidified potassium dichromate?
3
Name the major product when propene reacts with water in the presence of an acid catalyst.
4
Match each reaction to its type.
5
Balance the complete combustion of pentane, , with the smallest whole-number coefficients. What is the coefficient of ?
6
What mass of forms when 11.6 g of butane burns completely? Use C = 12.01, H = 1.01, O = 16.00 and give 3 significant figures.
g
7
Name the ester formed when ethanoic acid reacts with propan-1-ol.
8
2-methylpropan-2-ol is warmed with orange acidified potassium dichromate. What is observed?
9
Ethanoic acid can be made from ethene in three steps (hydration, then two oxidations). Order the compounds along the route.
  1. 1ethanol
  2. 2ethanoic acid
  3. 3ethanal
  4. 4ethene
10
Which compound turns orange-brown bromine water colourless quickly at room temperature?
11
Methyl ethanoate, , is hydrolyzed with an acid catalyst. What are the products?

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