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Lesson 2 of 5Molecular Genetics
Unit 3 · Lesson 2 of 5

DNA Replication and Repair

Why DNA copying is semiconservative and how Meselson and Stahl proved it, the enzymes at the replication fork, leading and lagging strands, how proofreading and repair keep errors rare, and why the ends of chromosomes need telomeres.

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Key things to remember

  1. 1Replication is semiconservative: each daughter helix has one parental strand and one new strand (Meselson and Stahl, 1958, using and ).
  2. 2DNA polymerase adds nucleotides only to a free 3'-OH, so new strands grow 5'→3', the template is read 3'→5', and a primer is required.
  3. 3At the fork: helicase unwinds, SSBs stabilize, topoisomerase relieves twisting, primase primes, pol III extends, pol I replaces primers, ligase seals.
  4. 4Leading strand: continuous, toward the fork. Lagging strand: discontinuous Okazaki fragments, built away from the fork.
  5. 5Error control: proofreading (during), mismatch repair (just after), excision repair (damage at any time); final error rate about 1 in .
  6. 6Telomerase extends telomere repeats (TTAGGG in humans) at the ends of linear chromosomes.

Each time one of your cells divides, it copies about 6.4 billion base pairs in a few hours and leaves only about one uncorrected error per billion nucleotides. Watson and Crick saw how this could work as soon as they built their model: because the two strands are complementary, each strand holds all the information needed to rebuild the other. As they put it in 1953, "It has not escaped our notice that the specific pairing we have postulated immediately suggests a possible copying mechanism for the genetic material." The details turned out to be intricate, because the helix must be unwound without tangling, and the copying enzyme obeys a strict rule about which direction it can build. Understand that one directional rule and almost everything else in this topic follows from it.

Three hypotheses and the Meselson–Stahl experiment

Three models were proposed. In semiconservative replication, the parent strands separate and each serves as a template, so every new double helix has one old strand and one new strand. In conservative replication, the original helix stays intact and a brand-new copy is made. In dispersive replication, every strand ends up as a patchwork of old and new pieces. In 1958 Matthew Meselson and Franklin Stahl grew E. coli for many generations on a medium whose only nitrogen source was heavy nitrogen, . Every base contains nitrogen, so all the bacteria's DNA became heavy. They then moved the bacteria to ordinary medium and took samples after each round of replication. To tell heavy from light DNA they used cesium chloride density-gradient centrifugation: spun at very high speed, each DNA molecule settles at the level where its density matches the salt solution, so heavy, hybrid and light DNA form separate bands.

Generations in 14NConservative predictsSemiconservative predictsDispersive predictsObserved
01 heavy band1 heavy band1 heavy band1 heavy band
11 heavy band + 1 light band1 intermediate (hybrid) band1 intermediate band1 intermediate band
21 heavy band + 1 light band (3 times as much light)1 intermediate band + 1 light band1 single band between intermediate and light1 intermediate band + 1 light band
Generation 1 ruled out conservative replication; generation 2 ruled out dispersive replication. Only the semiconservative model fits both.

Origins, bubbles and the replication fork

Replication begins at specific sequences called origins of replication, which tend to be rich in A–T pairs (they have only two hydrogen bonds each, so they separate more easily). The strands open into a replication bubble, and copying proceeds in both directions from the origin, so each bubble has two replication forks: Y-shaped regions where the parent helix is being unzipped. The circular chromosome of E. coli has a single origin; its two forks each travel at about 1000 nucleotides per second and meet on the far side of the circle. Eukaryotic chromosomes are far longer and their polymerases slower (about 50 nucleotides per second), so each chromosome has thousands of origins, and the bubbles grow until they merge.

The replication forkparental (template) DNAnew DNARNA primerDNA polymerase adds nucleotides only to a free 3′ end, so every new strand grows 5′ → 3′.fork movesLeading strand: made continuously, 5′ → 3′, toward the forkLagging strand: Okazaki fragments, each made 5′ → 3′ away from the fork3′5′3′5′5′3′3′5′topoPol IIIligasePol IPol IIIprimasetopoisomeraserelieves overwindinghelicase unwinds DNA,breaking H-bondsSSBs (single-strandbinding proteins) keepthe strands apartDNA ligaseseals the nickDNA pol Iswaps RNA primerfor DNADNA pol IIIextends eachfragmentprimaselays RNAprimers
Fig 1A replication fork: helicase unwinds, primase lays RNA primers, DNA polymerase III builds the leading strand continuously and the lagging strand in Okazaki fragments, then DNA polymerase I and ligase finish the job.
ProteinJob at the fork
HelicaseUnwinds the double helix by breaking the hydrogen bonds between base pairs; moves ahead of the fork.
Single-strand binding proteins (SSBs)Coat the exposed single strands so they do not pair back up or fold on themselves, and protect them from nucleases.
Topoisomerase (DNA gyrase in bacteria)Works ahead of the fork. Unwinding over-twists the DNA further along, like twisting a rope; topoisomerase cuts the backbone, lets the strain release, and rejoins it.
PrimaseAn RNA polymerase that builds a short RNA primer (about 5–10 nucleotides) on the template, giving DNA polymerase a free 3'-OH to start from.
DNA polymerase IIIThe main copying enzyme in prokaryotes. Adds DNA nucleotides to the 3' end of the primer or growing strand, so the new strand grows 5'→3' while the template is read 3'→5'. Also proofreads.
DNA polymerase IRemoves the RNA primers and replaces them with DNA nucleotides.
DNA ligaseSeals the last nick in the sugar-phosphate backbone by forming a phosphodiester bond, joining Okazaki fragments into a continuous strand.
DNA polymerase IIMainly a repair enzyme; it can also restart replication that has stalled at damaged DNA.
The prokaryotic (E. coli) replication machinery. Eukaryotes use different polymerases (such as α, δ and ε) that do the same jobs.
Why direction matters
DNA polymerase can only attach a new nucleotide to the free 3'-OH of an existing chain. That single rule has two consequences: the polymerase cannot start a strand from nothing (it needs a primer), and every new strand grows 5'→3'. Because the new strand is antiparallel to its template, the polymerase reads the template 3'→5'. The energy for each addition comes from the incoming nucleotide itself: it arrives as a deoxyribonucleoside triphosphate (dNTP) and releases two of its three phosphates as it joins the chain.

At each fork the two template strands point in opposite directions, but the fork moves only one way. On one template, DNA polymerase III can follow right behind the helicase and build continuously toward the fork; the new strand made this way is the leading strand, and it needs only one primer. On the other template, building 5'→3' means moving away from the fork. The polymerase makes a short stretch, then has to go back near the fork and start again from a new primer as more template is exposed. This strand, built in pieces, is the lagging strand, and the pieces are Okazaki fragments (about 1000–2000 nucleotides long in bacteria and 100–200 in eukaryotes), named after Reiji and Tsuneko Okazaki, who discovered them in the 1960s.

  1. Helicase exposes a new stretch of lagging-strand template.
  2. Primase lays down an RNA primer near the fork.
  3. DNA polymerase III extends the primer 5'→3', away from the fork, until it reaches the primer of the previous fragment.
  4. DNA polymerase I removes the old RNA primer and fills the gap with DNA.
  5. DNA ligase seals the remaining nick, joining the fragments into one strand.

Proofreading and repair

DNA polymerase inserts the wrong base roughly once in every 100 000 nucleotides. Without correction, every human cell division would add tens of thousands of mutations. Three layers of checking reduce the final error rate to about one in a billion, and they also fix damage that happens long after replication.

  • Proofreading (during replication): DNA polymerases III and I check each base right after adding it. If it is mispaired, the enzyme backs up, removes it (its 3'→5' exonuclease activity) and tries again. This alone improves accuracy about 100-fold.
  • Mismatch repair (just after replication): repair proteins scan the new DNA for mispaired bases that slipped past proofreading. In E. coli they can tell which strand is new because the parent strand already carries methyl tags. They cut out a section of the new strand around the error, and a polymerase and ligase rebuild it correctly.
  • Excision repair (any time): damage such as UV-induced thymine dimers or chemically altered bases distorts the helix. A nuclease cuts out the damaged stretch, DNA polymerase (pol I in bacteria) fills the gap using the undamaged strand as a template, and ligase seals it. People with the inherited disorder xeroderma pigmentosum lack a working excision-repair enzyme and develop skin cancers after very little sun exposure.
Telomeres and telomerase
Linear eukaryotic chromosomes have a problem at their ends. When the last RNA primer at the end of a lagging strand is removed, there is no upstream 3'-OH for a polymerase to extend, so a short stretch at the tip is left uncopied and the chromosome gets slightly shorter with every replication. Chromosome ends are therefore capped by telomeres: hundreds to thousands of repeats of a short non-coding sequence (TTAGGG in humans) that act as a disposable buffer, so genes are not lost. Most body cells lose some telomere each division, which contributes to cell aging. Telomerase, an enzyme that carries its own RNA template, adds new repeats to the 3' end. It is active in germ cells, stem cells and most cancer cells, which is one reason cancer cells can keep dividing. Circular bacterial chromosomes have no ends, so they have no end-replication problem.

Worked examples

Reveal one step at a time and try to beat it to the next line.

Example 1
Bacteria whose DNA is entirely are moved to medium. Assuming semiconservative replication, what fraction of DNA molecules is hybrid (/) and what fraction is light after 3 generations?
Example 2
A stretch of template strand reads 3'-TACGGATC-5', drawn left to right, and the replication fork is opening toward the right. (a) Write the new strand with its ends labelled. (b) Which way does the new strand grow? (c) Is it the leading or the lagging strand?
Example 3
The E. coli chromosome has base pairs and one origin. Each of its two forks copies about 1000 base pairs per second. (a) What is the minimum time to copy the chromosome, in minutes? (b) Human chromosome 1 has about base pairs and eukaryotic forks move about 50 base pairs per second. How long would it take with only one origin?

Where marks get lost

  • Saying the lagging strand is built 3'→5'. Both new strands are built 5'→3'; the lagging strand is discontinuous precisely because the polymerase cannot build in the other direction.
  • Mixing up polymerases I and III. Pol III does most of the synthesis; pol I removes RNA primers and fills those gaps. Ligase, not a polymerase, seals the final nick.
  • Thinking helicase breaks covalent bonds, or that topoisomerase unzips DNA. Helicase breaks the hydrogen bonds between bases; topoisomerase relieves the twisting strain ahead of the fork by cutting and rejoining the backbone.
  • Forgetting that primers are RNA. Primase is an RNA polymerase, which is exactly why the primers must later be removed and replaced with DNA.
  • Treating the Meselson–Stahl generation-1 result as full proof. One intermediate band rules out only conservative replication; the generation-2 bands were needed to rule out dispersive replication.

Flashcards 9

Semiconservative replication
Okazaki fragment
Helicase
Primase
+ 5 more

Practice

1
In the Meselson–Stahl experiment, what did the DNA look like after two generations in medium?
2
Bacteria with all- DNA replicate for 4 generations in medium. What percentage of the DNA molecules are hybrid?
%
3
Put these events on the lagging strand in the order they happen.
  1. 1DNA polymerase I replaces the RNA primer with DNA
  2. 2DNA polymerase III extends the primer 5' to 3'
  3. 3DNA ligase seals the nick in the backbone
  4. 4Helicase unwinds the double helix
  5. 5Single-strand binding proteins hold the strands apart
  6. 6Primase adds an RNA primer
4
Match each protein to its job in replication.
Helicase
Topoisomerase
Primase
DNA polymerase III
DNA polymerase I
DNA ligase
5
Why is the lagging strand made in short pieces?
6
What are the short DNA segments made on the lagging strand called?
7
A template strand reads 3'-CCGATA-5'. Write the new strand in the 5'→3' direction (letters only).
8
A bacterial chromosome has base pairs and one origin. Each of its two forks copies 750 base pairs per second. How many minutes does replication take? Give 2 significant figures.
min
9
Skin cells exposed to UV light develop thymine dimers. Which system removes this damage?
10
If DNA polymerase could start a new strand on its own, which enzyme would the cell no longer need?
11
Why do the chromosomes of most human body cells get slightly shorter each time they are replicated?

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