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Lesson 2 of 4Algebraic Expressions and Equations
Unit 3 · Lesson 2 of 4

Equivalent Expressions and Simplifying

Collect like terms, use the distributive property to expand brackets, and check whether two expressions are equivalent with substitution, tiles, graphs and algebra.

7 min read6 quick checks11 practice questionsAsk AI about this →

Key things to remember

  1. 1Like terms have the same variables with the same exponents; collect them by adding coefficients: .
  2. 2Distributive property: . Multiply every term inside the brackets.
  3. 3A negative outside brackets changes every sign inside: and .
  4. 4Two expressions are equivalent if they are equal for every value of the variable. One value where they differ proves they are not equivalent.
  5. 5A zero pair ( and ) has value and can be removed.

A square pool measures metres by metres, and a border of 1-metre square tiles goes all the way around it. Three friends write a rule for the number of border tiles. Aisha counts the four sides and then the four corners: . Ben splits the border into four equal strips, each tiles long: . Chen counts the top and bottom rows of tiles, then the two sides of tiles: . They look different, but try a 5 m pool: , and . Expressions that give the same value for every value of the variable are called equivalent expressions. This lesson shows you how to simplify expressions and how to prove (or disprove) that two of them are equivalent.

Like terms

Like terms have exactly the same variable part: the same letters raised to the same exponents. Only the coefficients can differ. So and are like terms, and are like terms, and all constants (like and ) are like terms. But and are not alike, and neither are and . To collect like terms, add their coefficients and keep the variable part the same. The reason is the same as counting objects: 3 apples plus 5 apples is 8 apples, not 8 "apples squared". In the same way, . Unlike terms can't be combined into one term: stays as it is, just as 3 apples plus 2 oranges is not 5 of anything.

PairLike terms?Why
and yessame variable, x
and yessame variable and same exponent
and yesxy and yx are the same product
and yesboth constants
and nodifferent exponents
and nodifferent variables
and noone has a variable, one does not
x= x1= 1−1= −11−1= 0 (a zero pair)Distributive property: 2(x + 3)x111group 1: x + 3x111group 2: x + 3put like tiles togetherxx1111112 x tiles6 unit tiles2(x + 3) = 2x + 6Collect like terms: (3x + 2) + (x − 5)xxx113x + 2x−1−1−1−1−1x − 5collect like tiles, cancel zero pairsxxxx4x1−101−10−1−1−1−3 left over(3x + 2) + (x − 5) = 4x − 3
Fig 1Algebra tiles. Left: two groups of x + 3 regroup into 2x + 6. Right: (3x + 2) + (x − 5) collects to 4x − 3 after two zero pairs cancel.

Algebra tiles make collecting like terms visible. A long tile stands for , a small square stands for , and a tile in the negative colour stands for . One positive unit tile and one negative unit tile together make , a zero pair, so you can remove them without changing the value. In the right half of the figure, becomes 4 long tiles, plus 2 positive and 5 negative unit tiles. Two zero pairs cancel and 3 negative tiles are left: . Grouping like terms in writing does the same job: and .

Quick checkTry it before you read on
1
Which pair are like terms?
Quick checkTry it before you read on
2
Simplify .
VideoJensenMath, an Ontario teacher, shows how to spot like terms and collect them, keeping each term's sign attached, in a Grade 9 lesson.Watch on YouTube

The distributive property

Multiply the number outside the brackets by every term inside.

The distributive property says that multiplying a sum by a number is the same as multiplying each part and then adding. In the left half of the figure, means two groups of , which is 2 long tiles and 6 unit tiles: . Every term inside the brackets gets multiplied, not just the first one. Watch the signs when the number outside is negative: because a negative times a negative is positive. A minus sign in front of brackets means multiply by : . Writing the expression without brackets is called expanding.

Area model: 3(x + 4)x433x3 × x = 3x3 × 4 = 123(x + 4) = 3x + 12The whole area is the sum of the two parts.Every term inside is multiplied−2(x−4)(−2) × x = −2x(−2) × (−4) = +8negative × negative−2(x − 4) = −2x + 8Not −2x − 8: the −2 multiplies the −4 too.
Fig 2Left: a rectangle 3 tall and x + 4 wide splits into areas 3x and 12, so 3(x + 4) = 3x + 12. Right: −2 multiplies both x and −4, giving −2x + 8.
Expand both brackets (the second with −2), then collect like terms.
Quick checkTry it before you read on
1
Expand .
Quick checkTry it before you read on
2
Expand .
VideoMath Antics explains the distributive property: the number outside the brackets multiplies every term inside, not just the first one.Watch on YouTube

Checking whether two expressions are equivalent

There are four ways to check. Algebra: simplify both expressions; if they simplify to the same thing, they are equivalent. Aisha's, Ben's and Chen's rules all simplify to . Substitution: put the same value into both. If the results differ for even one value, the expressions are not equivalent; one counterexample settles it. A match at one value does not prove equivalence, though: and both give when , but at they give and . For linear expressions in one variable (no exponents above 1), matching at two different values is enough, because their graphs are straight lines and two points fix a line. Graphs: equivalent expressions graph as the exact same line or curve. Tiles: equivalent expressions can be built from the same set of tiles once zero pairs are removed.

Equivalent: exactly the same lineOne match is not enough2x and x² agree at x = 0 and x = 2, not at x = 381624012345n4 short4n + 44(n + 1)4n48120123xx = 2: both 4x² = 92x = 62xx²
Fig 3Left: every point of 4(n + 1) lies on the line of 4n + 4, while the dashed line 4n is 4 lower everywhere. Right: the line 2x and the curve x² meet at x = 0 and x = 2 but give 6 and 9 at x = 3.
Pool side n (m)4n + 44(n + 1)2(n + 2) + 2n4n (missing corners)
18884
21212128
524242420
1044444440
Three equivalent border rules agree for every pool; the rule 4n is always 4 short because it misses the corner tiles.
AEquivalent
  • and
  • and
  • and
  • and
BNot equivalent
  • and (try : 6 vs 3)
  • and (try : 10 vs 20)
  • and (try : 8 vs 6)
  • and (try : 3 vs −3)
Pick a test value that can catch a difference
Values like and hide differences: , and are all equal at and again at . Test with something like or instead. If the values match, simplify algebraically to be sure.
Quick checkTry it before you read on
1
Which test value would not reveal that and are different?
Quick checkTry it before you read on
2
Two linear expressions in give the same value at and again at . What can you conclude?

Worked examples

Reveal one step at a time and try to beat it to the next line.

Example 1
Simplify .
Example 2
Expand and simplify .
Example 3
Show that Chen's rule is equivalent to Ben's rule .
Example 4
Kai says the number of border tiles around an by pool is . Is Kai's rule equivalent to ?

Where marks get lost

  • Combining unlike terms: writing , or . Only terms with the same variable part combine.
  • Changing the exponent when adding: , not . Adding like terms changes the coefficient only.
  • Distributing to the first term only: is wrong; it is .
  • Losing a sign with a negative outside: is , not , because .
  • Deciding two expressions are equivalent because they match at one value (often or ). One match proves nothing; one mismatch proves they are not equivalent.

Flashcards 8

Like terms
Collecting like terms
Distributive property
+ 4 more

Practice

1
Simplify .
2
Which term is a like term with ?
3
Expand .
4
Simplify , then evaluate the result when .
5
Which expression is equivalent to ?
6
Expand and simplify .
7
Match each expression to its simplified form.
  1. A.
  2. B.
  3. C.
  4. D.
  5. E.
8
Pat substitutes into and into and gets 2 both times. What can Pat conclude from these two results alone?
9
A square pool is 12 m by 12 m. How many 1 m square tiles are needed for a border one tile wide all the way around it?
tiles
10
Put these steps in order to simplify 3(2x − 1) − 2(x + 4).
  1. 1Group like terms: 6x − 2x − 3 − 8
  2. 2Check with x = 1: both the original and 4x − 11 give −7
  3. 3Combine: 4x − 11
  4. 4Expand both brackets: 6x − 3 − 2x − 8
11
What is ?

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