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Lesson 3 of 4Linear Systems
Unit 1 · Lesson 3 of 4

Solving by Elimination

Elimination adds or subtracts the two equations so that one variable cancels. Multiply one or both equations first so a pair of coefficients match, then solve, back-substitute and check. Learn when elimination beats substitution or graphing.

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Key things to remember

  1. 1Opposite coefficients ( and ): add the equations. Equal coefficients ( and ): subtract them.
  2. 2Multiplying every term of an equation by the same non-zero number gives an equivalent equation (the same line).
  3. 3To match coefficients, multiply to their lowest common multiple, e.g. and both become .
  4. 4If every variable cancels: a true statement () means infinitely many solutions; a false statement () means no solution.
  5. 5Choose elimination for two standard-form equations, substitution when a variable is already isolated, graphing for a picture or estimate.

Two friends stop at a café. Maya buys 3 hot chocolates and 2 bagels for $13. Jonah buys 5 hot chocolates and 2 bagels for $19. Neither receipt shows the price of a single item, but you can still work it out. Both orders include the same 2 bagels, so the only difference between them is that Jonah bought 2 more hot chocolates, and he paid $6 more. So 2 hot chocolates cost $6, and one costs $3. That idea, comparing two equations so that one variable cancels out, is the elimination method. In algebra you write the comparison as subtracting one equation from the other.

Why adding or subtracting equations works

An equation says that its two sides are equal amounts. If and , then and : adding equal amounts to equal amounts keeps things equal. So you may add (or subtract) the left sides of two equations and the right sides, and the result is still a true equation at the solution. The goal is to choose the operation that makes one variable disappear. If a variable has opposite coefficients, like and , add the equations. If it has the same coefficient, like and , subtract them. Here is a system with opposite -coefficients:

When the coefficients do not match: multiply first

Most systems do not arrive with matching coefficients, so you create them. Multiplying every term of an equation by the same non-zero number gives an equivalent equation: it describes the same line. In and , multiply the first equation by to get . Now the -coefficients are and , so adding gives and ; then gives . Sometimes you must multiply both equations. In and , no coefficient is a multiple of its partner. To eliminate , aim for the lowest common multiple of and , which is : multiply the first equation by and the second by , as the figure shows.

Original systemMake both x-terms 6x(1)(2)3x+4y=102x−3y=1× 2× 36 is the lowest commonmultiple of 3 and 26x+8y=206x−9y=3017y=17−subtractx is goneSubtract column by columnx-terms: 6x − 6x = 0, so x is eliminatedy-terms: 8y − (−9y) = 8y + 9y = 17ynumbers: 20 − 3 = 17Solve:17y = 17, so y = 1Back-substitute into (1):3x + 4(1) = 10, so 3x = 6 and x = 2Check in (2):2(2) − 3(1) = 4 − 3 = 1 ✓Solution: (2, 1)
Fig 1Solving 3x + 4y = 10 and 2x − 3y = 1 by elimination: multiply by 2 and by 3 so both x-terms become 6x, subtract column by column to get 17y = 17, then back-substitute to find x = 2 and check.
  1. Write both equations in the same form, , with like terms lined up in columns.
  2. Choose a variable to eliminate. Multiply one or both equations so that its coefficients are equal or opposite.
  3. Add the equations if the coefficients are opposite; subtract if they are equal. Combine every column, including the constants.
  4. Solve the resulting one-variable equation.
  5. Back-substitute into either original equation to find the other variable.
  6. Check the ordered pair in both original equations.
VideoWorked examples of multiplying one or both equations so that a variable cancels when the equations are added or subtracted.Watch on YouTube

Choosing a method

MethodWorks best whenWatch out for
GraphingBoth lines are easy to draw ( or whole-number intercepts) and you want a picture or an estimateAnswers that are not whole numbers can only be estimated
SubstitutionOne equation is already solved for a variable, or a variable has coefficient or Fractions if no coefficient is 1 or −1; forgotten brackets
EliminationBoth equations are in standard form , especially when no coefficient is or Sign errors when subtracting; multiplying only part of an equation
All three methods give the same solution; the choice is about speed and accuracy
Clear fractions and decimals first
Multiply an equation by the lowest common denominator of its fractions, or by or to clear decimals, before you eliminate. For , multiply every term by : . For , multiply every term by : . Whole-number coefficients are much harder to get wrong.

Elimination reveals the special cases the same way substitution does. Solve and : multiply the first equation by to get , then subtract the second. Every term cancels and you get , a true statement, so the equations describe the same line and there are infinitely many solutions. Change the second equation to and the same steps give , a false statement, so the lines are parallel and there is no solution.

Loading interactive…
Enter two equations in standard form, choose elimination, and follow every step of the working, including what happens with parallel lines and the same line.
Subtracting is where most errors happen
When you subtract an equation, you subtract every term, so a negative term changes sign: . To avoid this, you can multiply the equation you would subtract by and then add instead. Either way, put the subtracted equation in brackets.

Worked examples

Reveal one step at a time and try to beat it to the next line.

Example 1
A café receipt shows 3 hot chocolates and 2 bagels for $13, and another shows 5 hot chocolates and 2 bagels for $19. Find the price of each item.
Example 2
Solve by elimination: and .
Example 3
Solve by elimination: and .
Example 4
Solve: and .

Where marks get lost

  • Multiplying only one side, or only some terms: times 2 is , not .
  • Sign errors when subtracting: gives , not , because subtracting adds .
  • Adding when the coefficients are equal (or subtracting when they are opposite). does not eliminate anything; equal coefficients need subtraction.
  • Finding one variable and stopping. Elimination gives (or ); back-substitute for the other and state the ordered pair.
  • Rounding decimals like instead of clearing fractions first, which produces an answer that does not check exactly.

Flashcards 8

Elimination method
Opposite coefficients (e.g. +3y and −3y)
Equal coefficients (e.g. 2b and 2b)
Equivalent equation
+ 4 more

Practice

1
Solve and by elimination. What is the value of ?
2
Which plan eliminates from and ?
3
Finish solving and . What is the value of ?
4
Which equation is the result of multiplying by ?
5
Subtract the second equation from the first: and . Which equation do you get?
6
While solving a system by elimination, every variable cancels and you are left with . What does this mean?
7
Solve and . What is the value of ?
8
Solve and . What is the value of ?
9
Put the steps for solving 3x + 2y = 16 and x − 4y = −4 by elimination in order.
  1. 1Check (4, 2) in both original equations
  2. 2Back-substitute: 3(4) + 2y = 16, so y = 2
  3. 3Divide by 7: x = 4
  4. 4Multiply the first equation by 2: 6x + 4y = 32
  5. 5Add the new equation to x − 4y = −4: 7x = 28
10
Match each system to the method that suits it best and the reason.
y = 4x − 3 and 2x + 5y = 18
5x + 2y = 9 and 3x − 2y = 7
Estimate where y = 2x + 1 and y = −x + 4 cross, and see the picture

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